Answer:
67.5 moles of O2
Explanation:
2 C
8
H
18 + 27
O
2 → 16
C
O
2 + 18
H
2
O
According to the balanced chemical equation, in normal air % moles of iso-octane will require 67.5 moles of oxygen to combust completely...
Answer : The metal used was iron (the specific heat capacity is 
).
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of metal = ?
= specific heat of water = 
= mass of metal = 47.1 g
= mass of water = 120 g
= final temperature of water = 
= initial temperature of metal = 
= initial temperature of water = 
Now put all the given values in the above formula, we get
Form the value of specific heat of metal, we conclude that the metal used in this was iron.
Therefore, the metal used was iron (the specific heat capacity is ).
1 mole --------------------------- 6.02 x 10²³ molecules
( moles lithium ) --------------- 1.2 x 10²¹ molecules
( moles lithium ) = (1.2 x 10²¹ ) x 1 / ( 6.02 x 10²³ )
= 1.2 x 10²¹ / 6.02 x 10²³
= 2.0 x 10⁻³ moles of lithium
Answer D
hope this helps!
amount of ammonia injected:
72.3 kg/min x 12 min = 867.6 kg
ammonia concentration = 0.382%
Answer:
Peanut: 3.2 Calories per gram
Cheeto: 0.19 Calories per gram
(btw I wasn't given a nutrition label for either & on nutrition labels there are no "Calories per gram" so I'm a bit confused)
Explanation:
h
