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Tamiku [17]
3 years ago
10

Epidemiology deals primarily with what type of hazards?

Physics
2 answers:
MissTica3 years ago
7 0
The answer would be : <span>biological hazards.

Hope this helps !

Photon</span>
Illusion [34]3 years ago
4 0
It deals with skin diseases
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Discuss how the hardness or softness of the landing surface is related to the time required to stop the egg
monitta

Answer

To understand this concept it is necessary to understand Newton's Second Law

According to Newtons Second law applied force is equal to rate of change of momentum of a body.

Mathematically,

F=\frac{dp}{dt}

here, \frac{dp}{dt} is rate of change of momentum with respect to time

It means If two eggs fall from same height,one on softer surface and other on hard surface that time the momentum of both eggs will remain equal at both the surfaces. But, impact time will be different. On hard surface egg will stop almost instantly so impact time will be small and hence the force on egg will be large therefore the egg will breakup.

On the other hand on the soft surface like a cotton, egg will not stop instantly but it will slow down for a few seconds and then stop due to which the time of impact will increase. Therefore the force on egg will be less and it won't break up.


3 0
3 years ago
Why are Murcury, venus, earth and mars called the "terrestrial" planets?
Fittoniya [83]

Mercury, Venus, Earth, and Mars are considered terrestrial planets because those planets are mainly composed of metal or rock and are closest to the sun.

5 0
2 years ago
According to Newton's 3rd Law, an object's momentum depends on it's velocity and mass. 4 dog-sled teams competed to see who coul
podryga [215]

Answer:

C.) Sled Team C 28 kg moving at 12m/s

I'm pretty sure.

7 0
3 years ago
Mike says, I gave up guitar because I’ll never be good at it, some people seem to have a good ear music, not me. Which mindset i
AveGali [126]
A negative mind set
8 0
2 years ago
I will mark as the brainliest answer<br><br>plz 8,9,10​
blagie [28]

Answer:

8.  acceleration = \dfrac{d(velocity)}{d(time)}  = 1 unit .

9. acceleration = \dfrac{d(velocity)}{d(time)}  = -1 unit.

10. acceleration = \dfrac{d(velocity)}{d(time)}  = 0 units.

Explanation:

8. i) acceleration = velocity / time

  ii) In this figure velocity = time

  iii) therefore acceleration = \dfrac{d(velocity)}{d(time)} = 1 unit .

9. i) acceleration = velocity / time

  ii) In this figure 4 = m + 5, therefore m = -1

     therefore velocity = (-0.5 \times time) + 5

  iii) therefore acceleration = \dfrac{d(velocity)}{d(time)}  = -1 units.

10.) velocity is constant at 2

     therefore acceleration = \dfrac{d(velocity)}{d(time)}  = 0 units

5 0
3 years ago
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