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2 years ago

A ball has a mass of 2 kg and is thrown with a force of 8 Newtons for .35 seconds. What is the ball's change in

Physics

1 answer:

Anna [14]2 years ago

6 0

Answer:

1.4s

Explanation:

Given parameters:

Mass of ball = 2kg

Force = 8N

Time = 0.35s

Unknown:

Change in velocity = ?

Solution:

To solve this problem, we use the expression obtained from Newton's second law of motion which is shown below:

Ft = m(v - u)

So;

Ft = m Δv

F is the force

t is the time

m is the mass

Δv is the change in velocity

8 x 0.35 = 2 x Δv

Δv = 1.4s

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Which of the following can be used as a measure of an object's inertia?

Leokris [45]

Answer:

Explanation:

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3 years ago

100 points

luda_lava [24]

Answer:

10.21m/s²

Explanation:

Radial acceleration, also known as centripetal acceleration, refers to the acceleration of an object along the circular radius. It can be calculated using the formula:

a(r) = v²/r

Where a(r) = radial acceleration

v = velocity

r = radius of the circular path

According to the information provided in the question, velocity (v) = 17.5m/s, radius = 30m. Hence;

a(r) = v²/r

a(r) = 17.5²/30

a(r) = 10.208333

a(r) = 10.21m/s²

5 0

3 years ago

A bullet with a mass of 0.04-kg is traveling horizontally at 1400 m/s when it strikes a stationary target that is balanced on th

hammer [34]

The speed of the target with the bullet lodged in it is 5.6 m/s.

<h3>What is speed?</h3>

This is the rate of change of distance.

To calculate the speed of the target and the bullet lodged, we use the formula below.

Formula:

V = mu/(m+M)............. Equation 1

Where:

V = Speed of the target and the bullet
m = mass of the bullet
M = mass of the target
u = Initial speed of the target

From the question,

Given:

m = 0.04 kg
u = 1400 m/s
M = 9.96 kg

Substitute these values into equation 1

V = (0.04×1400)/(0.04+9.96)
V = 56/10
V = 5.6 m/s

Hence, the speed of the target with the bullet lodged in it is 5.6 m/s.

Learn more about speed here: brainly.com/question/6504879

#SPJ1

4 0

2 years ago

Which element is stable and nonreactive?

const2013 [10]

The answer is D. Krypton (kr)

6 0

3 years ago

¿cual es la velocidad de un haz de electrones que marchan sin desviarse cuando pasan a traves de un campo magnetico perpendicula

Elina [12.6K]

Answer:

La velocidad del haz de electrones es 1.78x10⁵ m/s. Este valor se obtuvo asumiendo que el campo magnético dado (3500007) estaba en tesla y que la fuerza venía dada en nN.

Explanation:

Podemos encontrar la velocidad del haz de electrones usando la Ley de Lorentz:

$F = |q|vBsin(\theta)$ (1)

En donde:

F: es la fuerza magnética = 100 nN

q: es el módulo de la carga del electron = 1.6x10⁻¹⁹ C

v: es la velocidad del haz de electrones =?

B: es el campo magnético = 3500007 T

θ: es el ángulo entre el vector velocidad y el campo magnético = 90°

Introduciendo los valores en la ecuación (1) y resolviendo para "v" tenemos:

$v = \frac{F}{qBsin(\theta)} = \frac{100 \cdot 10^{-9} N}{1.6 \cdot 10^{-19} C*3500007 T*sin(90)} = 1.78 \cdot 10^{5} m/s$

Este valor se calculó asumiendo que el campo magnético está dado en tesla (no tiene unidades en el enunciado). De igual manera se asumió que la fuerza indicada viene dada en nN.

Entonces, la velocidad del haz de electrones es 1.78x10⁵ m/s.

Espero que te sea de utilidad!

7 0

3 years ago