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Svetllana [295]
4 years ago
7

The planet Krypton has a mass of 7.6 × 1023 kg and radius of 1.7 × 106 m. What is the acceleration of an object in free fall nea

r the surface of Krypton? The gravitational constant is 6.6726 × 10−11 N · m2 /kg2 . Answer in units of m/s 2 .
Physics
1 answer:
olga55 [171]4 years ago
5 0

Answer:

17.55 m/s²

Explanation:

Parameters given:

Mass of Krypton, M = 7.6 * 10^23 kg

Radius, R = 1.7 * 10^6 m

Gravitational constant, G = 6.6726 * 10^(-11) Nm²/kg²

Acceleration due to gravity of planet of mass M is given as:

g = GM/R²

Since the object is close to the surface of Krypton, we can say that the distance from the Centre of Krypton is the radius of the planet Krypton.

Therefore,

g = (6.6726 * 10^(-11) * 7.6 * 10^23)/(1.7 * 10^6)²

g = 17.55 m/s²

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Two ice skaters stand together. They push off and travel directly away from each other, the boy with a velocity of v = +0.35 m/s
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-0.55m/s

Explanation:

Given that: For the boy

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For the girl

Given that:

Weight = 477 N

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m = 48.62kg

To solve for the v of the girl, the two has to add up

48.62kg×v + 75.94kg×+0.35 m/s = 0

48.62v + 26.579 = 0

48.62v = - 26.579

v = -26.579/48.62

v = -0.5466

v = -0.55m/s

Hence, the velocity of the girl is -0.55m/s.

The negative sign is as a result of the two of them moving is opposite direction.

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3 years ago
Question: How is the energy in the food we eat an example of chemical potential energy?
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the shock absorbers in a car act as a big spring with k= 21900 N/m. when a 92.5 kg person gets in, how far does the spring stret
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Answer: 0.04139m

Explanation:

First, we need to calculate the weight of the man which will be:

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Weight = mg

Weight = 92.5 × 9.8

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Then, we calculate the force which will be:

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The spring stretched for 0.04139m.

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