The planet Krypton has a mass of 7.6 × 1023 kg and radius of 1.7 × 106 m. What is the acceleration of an object in free fall nea r the surface of Krypton? The gravitational constant is 6.6726 × 10−11 N · m2 /kg2 . Answer in units of m/s 2 .
1 answer:
Answer:
17.55 m/s²
Explanation:
Parameters given:
Mass of Krypton, M = 7.6 * 10^23 kg
Radius, R = 1.7 * 10^6 m
Gravitational constant, G = 6.6726 * 10^(-11) Nm²/kg²
Acceleration due to gravity of planet of mass M is given as:
g = GM/R²
Since the object is close to the surface of Krypton, we can say that the distance from the Centre of Krypton is the radius of the planet Krypton.
Therefore,
g = (6.6726 * 10^(-11) * 7.6 * 10^23)/(1.7 * 10^6)²
g = 17.55 m/s²
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