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QveST [7]
3 years ago
9

A water balloon was dropped from a high window and struck its target 1.1 seconds later. If the balloon left the person's hand at

-5.0 m/sec, what was its velocity on impact?
Physics
1 answer:
GrogVix [38]3 years ago
5 0
The acceleration of gravity on Earth is 9.8 meters per second every second.  So
in 1.1 second of falling, an object gains (9.8 x 1.1) = 10.78 meters per second of
downward speed.

The balloon was already falling at 5 m/sec when the time began, and it gained
another 10.78 m/sec on the way.  So at the end of 1.1 second, its downward
speed was (5.0 + 10.78) = 15.78 m/sec.

Its velocity was 15.78 m/sec downward. 
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Consider a rectangular ice floe 5.00 m high, 4.00 m long, and 3.00 m wide. a) What percentage of the ice floe is below the water
artcher [175]

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(a) 92 %

(b) 6.76 %

Explanation:

length, l = 4 m, height, h = 5 m, width, w = 3 m, density of water = 1000 kg/m^3

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(a) Let v be the volume of ice below water surface.

By the principle of flotation

Buoyant force = weight of ice block

Volume immersed x density of water x g = Total volume of ice block x density

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v x 1000 x g = V x 920 x g

v / V = 0.92

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(b) Let v be the volume of ice below the mercury.

By the principle of flotation

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