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QveST [7]
3 years ago
9

A water balloon was dropped from a high window and struck its target 1.1 seconds later. If the balloon left the person's hand at

-5.0 m/sec, what was its velocity on impact?
Physics
1 answer:
GrogVix [38]3 years ago
5 0
The acceleration of gravity on Earth is 9.8 meters per second every second.  So
in 1.1 second of falling, an object gains (9.8 x 1.1) = 10.78 meters per second of
downward speed.

The balloon was already falling at 5 m/sec when the time began, and it gained
another 10.78 m/sec on the way.  So at the end of 1.1 second, its downward
speed was (5.0 + 10.78) = 15.78 m/sec.

Its velocity was 15.78 m/sec downward. 
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Which of the following describes the charge of an atom before any electrons are transferred?
gregori [183]

The answer is neutral charge. An atom element will always and has to be stable, in order for this state to happen. The charge of an electron has to be neutral. For atom with neutral charge, the proton will always equal the number of electron.

8 0
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The Andromeda Galaxy (our nearest spiral neighbor) has spectral lines that show a blue shift. From this we may conclude that:
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<h3>What is Andromeda Galaxy?</h3>

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Therefore, this concludes that, the Universe has stopped expanding. This galaxy is slowly shifting towards us.

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8 0
2 years ago
A big wheel at a theme park has a diameter of 14m and people on the ride complete one revolution in 24s. calculate the distance
just olya [345]

Explanation:

We'll call the radius r and the diameter d:

We also assume that the riders are at a distance r = d/2 = 7m from the center of the wheel.

The period of the wheel is 24s. The tangent velocity of the wheel (and the riders) will be: (2pi/T)*r = 0.8 m/s (circa).

It means that in 3 minutes (180 seconds) they'll run 0.8 m/s * 180s = 144m.

Hopefully I understood the question. If yes, that's the answer.

7 0
2 years ago
A 200kg bucket of cement<br>​
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Yes. A 200 kg bucket of cement = About 440.925 pounds of cements.

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7 0
3 years ago
A small charged bead has a mass of 1.9 g . it is held in a uniform electric field e⃗ = (200,000 n/c, up). when the bead is relea
dmitriy555 [2]

As we know that when charge is released in electric field

It will have two forces on it

1. electrostatic force

2. gravitational force

now if the ball will accelerate upwards so we can say

net upward force = mass * acceleration

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q*200000 - 1.9 * 10^{-3}* 9.8 = 1.9 * 10^{-3}* 15

now we can find charge q on it by above equation

q = 0.2356 * 10^{-6} C

So above is the charge on the particle

7 0
3 years ago
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