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4 years ago

Stars that are composed of matter in which electrons have combined with protons are called ________.

Physics

1 answer:

Dovator [93]4 years ago

3 0

The answer will be neutral because the same number of protons and the same number of electrons

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In proton beam therapy, a beam of high-energy protons is used to kill cancerous cells in a tumor. In one system, the beam, which

Thepotemich [5.8K]

The number of protons that strike the tumor each second is $1.75 \times 10^8$ protons.

<u>Given the following data:</u>

Energy of proton = $2.8 \times 10^{-11}$ Joules.

Current = 84 nA to A = $84 \times 10^{-9}$ Ampere.

Energy of total dose = $3.4 \times 10^{-3}$ Joules.

<u>Scientific data:</u>

Charge of proton = $1.602 \times 10^{-19}$ C.

To determine the number of protons that strike the tumor each second:

<h3>How to determine the number of protons.</h3>

Mathematically, the quantity of charge per unit time is given by this formula:

$Q =It=Ne\\\\N = \frac{Q}{e}$

<u>Where:</u>

N is the number of protons.

t is the time measured in seconds.

I is the current.

e is the charge of protons.

Substituting the parameters into the formula, we have;

$N=\frac{2.8 \times 10^{-11} }{1.602 \times 10^{-19}} \\\\N = 1.75 \times 10^{8}$ protons.

Read more on charges here: brainly.com/question/14372859

8 0

2 years ago

3. Si usted duplicara la amplitud de un M.A.S. ¿cómo cambiaría la frecuencia, velocidad máxima, la aceleración máxima y la energ

WITCHER [35]

Answer:

Explanation:

la frecuencia = ω/2π, nada cambio

v(max) = ωA → ω2Α = 2ωA duplicara velocidad máxima

a(max) = ω²Α → ω²2Α = 2ω²Α duplicara la aceleración máxima

la energía total ½kA² → ½k(2Α)² = 4(½kA²) cuatro veces la energía

8 0

3 years ago

Answer this please. thanks in advance!! please tel me a christma

saw5 [17]

If 50 identical light bulbs are connected in series across
a single power source, then the voltage across each bulb
is ( 1/50 ) of the voltage delivered by the power source.

6 0

4 years ago

Read 2 more answers

Un vehicle surt, en un instant, d'un punt A cap a un altre punt B amb una velocitat constant de 36 km/h. Després d'un minut(60 s

kati45 [8]

Ask Siri or goggle has all answers

6 0

3 years ago

Suppose electrons in a TV tube are accelerated through a potential difference of 2.00 104 V from the heated cathode (negative el

Ivanshal [37]

Answer:

83816746.4254 m/s

Explanation:

m = Mass of electron = $9.11\times 10^{-31}\ kg$

q = Charge of electron = $1.6\times 10^{-19}\ C$

V = Voltage = $2\times 10^4\ V$

The kinetic energy of the electron is

$K=\dfrac{1}{2}mv^2$

Energy is given by

$E=qV$

Balancing the energy

$qV=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{\dfrac{2qV}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 2\times 10^4}{9.11\times 10^{-31}}}\\\Rightarrow v=83816746.4254\ m/s$

The velocity of the electrons is 83816746.4254 m/s

5 0

3 years ago