Question

If an object of mass m1 = 0.55 ???????? is sliding without friction in the +x-direction on a level surface at a speed of ????1 = 0.72 m/???? and it collides with a stationary object of mass m1 = 0.55 ????????, determine the total initial and total final momenta (before and after the collision) as well as the total initial and final Mechanical Energy (before and after the collision) for a perfectly elastic collision.

Answer 1

Answer:

$ME = 0.14 J$

$P = 0.396 kg m/s$

Explanation:

As we know that for perfectly elastic collision total mechanical energy is always conserved

so we will have

$ME = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2$

$ME = \frac{1}{2}0.55(0.72^2) + \frac{1}{2}0.55(0^2)$

$ME = 0.14 J$

now we also know that total moment of the system is conserved in any collision because there is no external force on it

so we will have

$P = m_1v_1 + m_2v_2$

$P = 0.55(0.72) + 0$

$P = 0.396 kg m/s$