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azamat
3 years ago
9

Boxers attempt to move with an opponent's punch when it is thrown. In other words, a boxer moves in the same direction as their

opponent's punch. This movement may prevent a knockout blow being delivered by their opponent. Explain how.
Physics
2 answers:
Bingel [31]3 years ago
8 0

Answer: h

Explanation:

Impulse is defined as the change of momentum of an object if the object is acted by a force for an interval of time. By delaying the time, the impact of the force can be reduced.

Boxers attempt to move with an opponent's punch when it is thrown. The force applied by the opponent's punch is extended over a longer time. Then the effect of the force of the blow can be reduced. In this case, the chances of a knockout blow being delivered by their opponent can be minimized.

maxonik [38]3 years ago
5 0
When the force of the opponent's punch is extended, with time, the effect of the blow or the force of the blow is reduced thereby reducing chances for a knockout punch from the opponent to the boxer.
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Answer:

Force = 125 [N]

Explanation:

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And if we make a sum of moments at the point O equal to zero (0).

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State Pascal's principle of transmission of pressure​
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Answer:

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4 0
3 years ago
A wave has a wavelength of 9 mm and a frequency of 6 hertz. What is its speed?
Marrrta [24]
Speed = (frequency)x(wavelength).

Frequency = 6 Hz
Wavelength = 9mm = 0.009m.

Speed = (6 Hz) x (0.009m) = 0.054 m/s   or   54 mm/sec.
5 0
3 years ago
A 50.0 Watt stereo emits sound waves isotropically at a wavelength of 0.700 meters. This stereo is stationary, but a person in a
photoshop1234 [79]

Answer:

a) f' = 432 Hz

b) I = 8.12*10^-4 W/m^2

Explanation:

a) To calculate the frequency of sound waves that car receives, you take into account the Doppler effect. In this case (observer moves away of the source) you have the following formula:

f'=f(\frac{v-v_o}{v+v_s})    (1)

where

f: frequency of the source = ?

v: speed of sound = 343 m/s

vo: speed of the observer = 40.0 m/s

vs: speed of the source = 0 m/s (stationary)

You replace the values of all parameters in the equation (1):

To calculate f' you first calculate the frequency of the sound wave, by using the following formula:

v=\lambda f\\\\

v: speed of sound

λ: wavelength = 0.700 m

f=\frac{v}{\lambda}=\frac{343m/s}{0.700m}=480Hz

Next, you replace the values of all parameters in the equation (1):

f'=(490Hz)(\frac{343m/s-40.0m/s}{343m/s})=432Hz

hence, the frequency perceived by the car is 432 Hz

b) To calculate the power of the sound wave, when the car is 70.0 maway from the speaker, you use the following formula:

I=\frac{P}{4\pi r^2}

P: power of the source = 50.0 W

r: distance to the source = 70.0 m

I=\frac{50.0 W}{4\pi(70.0m)^2}=8.12*10^{-4}\frac{W}{m^2}

hence, the intensity is 8.12*10^⁻4 W/m^2

3 0
3 years ago
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Here's link to the answer:

tinyurl.com/wpazsebu

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