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azamat
4 years ago
9

Boxers attempt to move with an opponent's punch when it is thrown. In other words, a boxer moves in the same direction as their

opponent's punch. This movement may prevent a knockout blow being delivered by their opponent. Explain how.
Physics
2 answers:
Bingel [31]4 years ago
8 0

Answer: h

Explanation:

Impulse is defined as the change of momentum of an object if the object is acted by a force for an interval of time. By delaying the time, the impact of the force can be reduced.

Boxers attempt to move with an opponent's punch when it is thrown. The force applied by the opponent's punch is extended over a longer time. Then the effect of the force of the blow can be reduced. In this case, the chances of a knockout blow being delivered by their opponent can be minimized.

maxonik [38]4 years ago
5 0
When the force of the opponent's punch is extended, with time, the effect of the blow or the force of the blow is reduced thereby reducing chances for a knockout punch from the opponent to the boxer.
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A scientific hypothesis starts with the lowest level of acceptance but can become stronger as they are used and survive repeated
Pachacha [2.7K]

Answer:

True.

Explanation:

Hypotheses are supposed to be tested, to be proven correct. They usually start from a small thought without 100% correct, but as you do further testing, they become stronger.

3 0
3 years ago
Read 2 more answers
a person can throw a 300 gram ball at 25 m/s the maximum height the person can throw the ball on Earth?​
jolli1 [7]

Answer:

Elevation =31.85[m]

Explanation:

We can solve this problem by using the principle of energy conservation. This consists of transforming kinetic energy into potential energy or vice versa. For this specific case is the transformation of kinetic energy to potential energy.

We need to first identify all the input data, and establish a condition or a point where the potential energy is zero.

The point where the ball is thrown shall be taken as a reference point of potential energy.

E_{p} = E_{k} \\where:\\E_{p}= potential energy [J]\\ E_{k}= kinetic energy [J]

m = mass of the ball = 300 [gr] = 0.3 [kg]

v = initial velocity = 25 [m/s]

E_{k}=\frac{1}{2}  * m* v^{2} \\E_{k}= \frac{1}{2} * 0.3* (25)^{2} \\E_{k}= 93.75 [J]

93.75=m*g*h\\where:\\g = gravity = 9.81 [m/s^2]\\h = elevation [m]\\replacing\\h=\frac{E_{k}}{m*g} \\h=\frac{93.75}{.3*9.81} \\h=31.85[m]

5 0
4 years ago
Starting at t = 0 a net external force in the +x-direction is applied to an object that has mass 5.00 kg. A graph of the force a
Reptile [31]

Answer:

  15√2 N

Explanation:

The acceleration is given by ...

  a = F/m = 5t/5 = t . . . . meters/second^2

The velocity is the integral of acceleration:

  v = ∫a·dt = (1/2)t^2

This will be 9 m/s when ...

  9 = (1/2)t^2

  t = √18 . . . . seconds

And the force at that time is ...

  F = 5(√18) = 15√2 . . . . newtons

6 0
3 years ago
A block of mass 0.84 kg is suspended by a string which is wrapped so that it is at a radius of 0.061 m from the center of a pull
lora16 [44]

Answer:

E_l = 1.713 J

Explanation:

Given data:

mass of block is M_b = 0.84 kg

radius of block = 0.061 m

moment of inertia is 6.20 \times 10^{-3} kg m^2

D is distance covered by block = 0.65 m

speed of block is 1.705 m/s

From conservation of momentum  we have

M_b g D = \frac{1}{2} M_b v^2 + \frac{1}{2} I \omega^2 +  E_{loss}

0.84 \times 9.81 \times 0.65 = \frac{1}{2}\times  0.84 \times 1.705^2 +\frac{1}{2} \times 6.2 \times 10^{-3} [\frac{1.705}{0.061}]^2 + E_l

solving for energy loss

E_l = 1.713 J

3 0
3 years ago
Resolve the vector shown below into its components.
yan [13]

Answer:

D. s=3x+4y

Explanation:

The line is at the 3rd column in the 4th row.

7 0
2 years ago
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