150 miles in 3 hours

Geometry math question no Guessing and Please show work thank you

Snezhnost [94]

3m+21=6m
=>21=6m-3m
=>21=3m
=>7=m
Therefore option A is the answer

7 0

3 years ago

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Find the mean and median for the graph?

netineya [11]

Answer:

so from looking at this we can see there is

0=5

1=5

2=3

3=2

4=4

5=1

6=2

7=2

8=1

9=1

now we have to add them up

5+6+16+5+12+14+8+9=75

and now we have to add up the total plots on the chart

5+5+3+2+4+1+2+2+1+1=26

now we divide

75 divided by 26=2.88461538462

so 2.9 is the mean

now we add up the number from least to greatest

0,0,0,0,0,1,1,1,1,1,2,2,2,4,4,4,4,5,6,6,7,7,8,9

so the medien is 4

Hope This Helps!!!

4 0

2 years ago

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A car travels for 4(t+3) hours at a constant speed of 10(t+3) km/h. If the total distance travelled by the car is 810 km, find t

IceJOKER [234]

Step-by-step explanation:

$\because \: time \times speed = distance \\ \therefore \: 4(t + 3) \times 10(t + 3) = 810 \\ \therefore \: 4(t + 3)^{2} = 81 \\ \therefore \: \{2(t + 3) \}^{2} = {9}^{2} \\ \therefore \: \{2(t + 3) \} = {9} \\ \therefore \: t + 3 = \frac{9}{2} \\ \therefore \: t = \frac{9}{2} - 3 \\ \therefore \: t = \frac{9 - 6}{2} \\ \therefore \: t = \frac{3}{2} \\ \therefore \: t = 1.5 \: hrs \\$

$\because \: time \times speed = distance \\ \therefore \: 4(t + 3) \times 10(t + 3) = 810 \\ \therefore \: 4(t + 3)^{2} = 81 \\ \therefore \: \{2(t + 3) \}^{2} = {9}^{2} \\ \therefore \: \{2(t + 3) \} = {9} \\ \therefore \: t + 3 = \frac{9}{2} \\ \therefore \: t = \frac{9}{2} - 3 \\ \therefore \: t = \frac{9 - 6}{2} \\ \therefore \: t = \frac{3}{2} \\ \therefore \: t = 1.5 \: hrs \\ speed \: of \: car = 10(t + 3) \\ \hspace{60 pt} = 10(1.5 + 3) \\ \hspace{60 pt}= 10 \times 4.5 \\ \red{ \boxed{ \bold{ \therefore \: speed \: of \: car = 45 \:km/ h}}} \\$