Answer:
The probability that this accountant has an MBA degree or at least five years of professional experience, but not both is 0.3
Step-by-step explanation:
From the given study,
Let A be the event that the accountant has an MBA degree
Let B be the event that the accountant has at least 5 years of professional experience.
P(A) = 0.35
= 1 - P(A)
= 1 - 0.35
= 0.65
= 0.45
P(B) = 1 -
P(B) = 1 - 0.45
P(B) = 0.55
P(A ∩ B ) = 0.75
P(A ∩ B ) = 0.75 [ 1 - P(A ∪ B) ] because =
SO;
P(A ∩ B ) = 0.75 [ 1 - P(A) - P(B) + P(A ∩ B) ]
P(A ∩ B ) = 0.75 [ 1 - 0.35 - 0.55 + P(A ∩ B) ]
P(A ∩ B ) - 0.75 P(A ∩ B) = 0.75 [1 - 0.35 -0.55 ]
0.25 P(A ∩ B) = 0.075
P(A ∩ B) =
P(A ∩ B) = 0.3
The probability that this accountant has an MBA degree or at least five years of professional experience, but not both is: P(A ∪ B ) - P(A ∩ B)
= P(A) + P(B) - 2P( A ∩ B)
= (0.35 + 0.55) - 2(0.3)
= 0.9 - 0.6
= 0.3
∴
The probability that this accountant has an MBA degree or at least five years of professional experience, but not both is 0.3
The total number of different routes that a fire truck can travel the m-distance from F to Z = 4 (Option C).
<h3 /><h3>What is a graph?</h3>
A graph refers to a diagram that shows how a variable varies in relation to one or more other variables, such as a collection of points, lines, line segments, curves, or regions.
Now,
Firstly, refer to the graph attached.
- The graph can be used to manually calculate the number of routes that lead from F to Z.
- F is four m-distances from Z.
- Now, manually calculate the m-distance of the path from F to Z using the 4 boxes that represent it. We discover 6 distinct pathways, each with an m-distance of 4.
Hence, The total number of different routes that a fire truck can travel the m-distance from F to Z = 4 (Option C).
To learn more about graphs, refer to the link: brainly.com/question/4025726
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Answer:
i believe it is a bc they are both equal but if wrong im sry
Step-by-step explanation:
Carina should've subtracted 3.40 from 5.27