All categories

2 years ago

Please someone help me? if you have a good answer I will gave U a brainlest :)

Physics

1 answer:

Natali5045456 [20]2 years ago

6 0

Answer:

for one its photo

Explanation: answers

this is easy 1. im not sure

2. erosion

3. is deposition

sorry i cant answer all of them but some simple ones deposition is when that stuff is getting moved, erosion is the breaking down of sokething and weathering is weather such as rain acid rain ice etc weather breeakin down rocks etc

You might be interested in

a car starts from the rest and accelerates at 9.54m/s for 6.5 seconds. what is the distance covered by the car

uysha [10]

Answer:

= 201.53 meters

Explanation:

A car started from rest and accelerated at 9.54 m/s^2 for 6.5 seconds. How much distance was covered by the car?

Use the formula d = $\frac{at^{2} }{2} ,$

where d is the distance, t is the time and "a" is the acceleration.
$d=\frac{9*54*6*5^{2} }{2} = 201.53 m$

3 0

1 year ago

A 62 kg bungee jumper jumps from a bridge. She is tied to a bungee cord whose unstretched length is 12 m. She falls a total of 3

Andrew [12]

Answer:

k = 104.46 N/m

Explanation:

Here we can use energy conservation

so we will have

initial gravitational potential energy = final total spring potential energy

as we know that she falls a total distance of 31 m

while the unstretched length of the string is 12 m

so the extension in the string is given as

$x = L - L_o$

$x = 31 - 12 = 19 m$

so we have

$mgH = \frac{1}{2}kx^2$

$62(9.81)(31) = \frac{1}{2}k (19^2)$

$k = 104.46 N/m$

5 0

2 years ago

The 49-g arrow is launched so that it hits and embeds in a 1.45 kg block. The block hangs from strings. After the arrow joins th

Dimas [21]

Answer:

the initial speed of the arrow before joining the block is 89.85 m/s

Explanation:

Given;

mass of the arrow, m₁ = 49 g = 0.049 kg

mass of block, m₂ = 1.45 kg

height reached by the arrow and the block, h = 0.44 m

The gravitational potential energy of the block and arrow system;

P.E = mgh

P.E = (1.45 + 0.049) x 9.8 x 0.44

P.E = 6.464 J

The final velocity of the system after collision is calculated as;

K.E = ¹/₂mv²

6.464 = ¹/₂(1.45 + 0.049)v²

6.464 = 0.7495v²

v² = 6.464 / 0.7495

v² = 8.6244

v = √8.6244

v = 2.937 m/s

Apply principle of conservation of linear momentum to determine the initial speed of the arrow;

$P_{initial} = P_{final}\\\\mv_{arrow} + mv_{block} = (m_1 + m_2)V\\\\0.049(v) + 1.45(0) = (0.049 + 1.45)2.937\\\\0.049v = 4.4026\\\\v = \frac{4.4026}{0.049} \\\\v = 89.85 \ m/s$

Therefore, the initial speed of the arrow before joining the block is 89.85 m/s

4 0

2 years ago

A thin block of soft wood with a mass of 0.072 kg rests on a horizontal frictionless surface. A bullet with a mass of 4.67 g is

kozerog [31]

Answer:

v’= 279.66 m / s

Explanation:

We work this exercise using the conservation of the moment. For this we define the system formed by the two blocks, therefore the forces during the collision are internal of the action and reaction type.

Initial instant. Before the crash

p₀ = m v₀ + 0

Final moment. After the crash

p_f = m v + M v ’

how the tidal wave is preserved

p₀ = p_f

m v₀ = m v + M v ’

v = $\frac{m v_o - Mv'}{m}$

let's calculate

v ’= $\frac{0.00467 \ 619 - 0.072 \ 22}{0.004676}$

v ’= $\frac{2.89- 1.584}{ 0.00467}$

v ’= 279.66 m / s

4 0

2 years ago

A car has a mass of 975 kg. by pushing on the car, evan increses its speed from 0.5 m/s to 3 m/s. what impulse did evan apply to

jarptica [38.1K]

Impulse = change in momentum = F x dt
Where F is sufficiently large and dt is very small(tending to zero).

Therefore impulse = mass x final velocity - mass x initial velocity
= 975 x 3 - 975 x 0.5
= 2437.5 Kg-m/s.
Hence option C is correct.

7 0

2 years ago

Read 2 more answers