All categories

1 year ago

Review. (b) What is the mass difference?

Physics

1 answer:

nignag [31]1 year ago

8 0

The mass difference is in between the two is equivalent to the binding energy of the nucleus .

<h3>What is meant by mass difference? </h3>

Δm be the mass difference is defined as the difference between the mass of the nucleus and the total mass of the individual nucleons that comprise it.

Binding energy is the energy required to split the nucleus of an atom into neutrons and protons, while mass defect is the difference between the predicted mass and the actual mass of the nucleus of an atom .

The mass difference is difference between the mass of nucleus and the Total mass of the individual nucleons that make it up.

∆m = final mass - initial mass.

To learn more about mass refer to:

brainly.com/question/19694949

#SPJ4

You might be interested in

A solution that has a high concentration of hydrogen ions has what type of pH?

Darya [45]

I believe the answer is A.

4 0

3 years ago

Read 2 more answers

Each of two small non-conducting spheres is charged positively, the combined charge being 40 μC. When the two spheres are 50 cm

Phantasy [73]

Answer:

1.44 x 10⁻⁶ C

Explanation:

$q_{1}$ = charge on one sphere

$q_{2}$ = charge on other sphere

$q$ = Total charge on the two spheres = 40 μC

$q_{1}+ q_{2}$ = $q$

$q_{1}+ q_{2}$ = 40 x 10⁻⁶

$q_{1}$ = (40 x 10⁻⁶) - $q_{2}$ eq-1

$r$ = distance between the two spheres = 50 cm = 0.50 m

$F$ = magnitude of force between the two spheres = 2.0 N

Magnitude of force between the two spheres is given as

$F = \frac{k q_{1} q_{2}}{r^{2}}$

$2.0 = \frac{(9\times 10^{9}) ((40\times 10^{-6}) - q_{2}) q_{2}}{0.50^{2}}$

$q_{2}$ = 1.44 x 10⁻⁶ C

7 0

3 years ago

Assume that a 4.00 kg pendulum bob is hanging from a 7.90 m long cable. The cable is attached to a hook in the ceiling 10 m up f

leonid [27]

Answer:

Explanation:

Given

mass of Pendulum m=4 kg

Length of cable= 7.90 m

Distance between roof and Floor=10 m

$mg\sin\theta$ will Provide Torque

thus $mg\sin \theta \times L=I\cdot \alpha$

where I=moment of inertia

$\alpha$ =angular acceleration

here $\theta$ is small therefore \sin \theta \approx \theta

$\frac{g}{L}\theta =\alpha$

thus $\omega ^2=\frac{g}{L}$

$\omega =\sqrt{\frac{g}{L}}$

And $T\cdot \omega =2\pi$

$T=2\pi \sqrt{\frac{L}{g}}$

$T=2\pi \sqrt{\frac{7.90}{9.8}}=5.64 s$

Small angle refers to any angle where

$\sin \theta \approx \theta$ i.e. any angle less than $15^{\circ}$

3 0

3 years ago

40 Points!!! Write a summary paragraph discussing this experiment and the results. Use the following questions to help guide the

Gnoma [55]

Answer:

sorry but i dont know can you brainliest me plsss i need it

7 1

2 years ago

Read 2 more answers

In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward

lukranit [14]

Answer:

3.8 × 10 ⁻¹⁴ m

Explanation:

The alpha particle will be deflected when its kinetic energy is equal to the potential energy

Charge of the alpha particle q₁= 2 × 1.6 × 10⁻¹⁹ C = 3.2 × 10⁻¹⁹ C

Charge of the gold nucleus q₂= 79 × 1.6 × 10⁻¹⁹ = 1.264 × 10⁻¹⁷C

Kinetic energy of the alpha particle = 5.97 × 10⁶ × 1.602 × 10⁻¹⁹ J ( 1 eV) = 9.564 × 10⁻¹³

k electrostatic force constant = 9 × 10⁹ N.m²/c²

Kinetic energy = potential energy = k q₁q₂ / r where r is the closest distance the alpha particle got to the gold nucleus

r = ( 9 × 10⁹ N.m²/c² × 3.2 × 10⁻¹⁹ C × 1.264 × 10⁻¹⁷C) / 9.564 × 10⁻¹³ = 3.8 × 10 ⁻¹⁴ m

6 0

3 years ago