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Arturiano [62]
3 years ago
6

The pressure of a gas is 1.0 atm, the volume is 3.0 L, and the temperature is 200 K. A chemist changes one factor while keeping

another constant so that the new pressure is 2.0 atm. Which of the following could be the new conditions?
The final volume is 6.0 L, while temperature is kept constant.
The final temperature is 100 K, while volume is kept constant.
The final volume is 4.0 L, while temperature is kept constant.
The final temperature is 400 K, while volume is kept constant.
Chemistry
1 answer:
anygoal [31]3 years ago
4 0

Answer: fourth statement is correct. The final temperature is 400 K, while volume is kept constant.

Explanation: At constant temperature, volume is inversely proportional to the pressure and,

At constant volume, pressure is directly proportional to the kelvin temperature.

Initially the gas pressure is 1.0 atm, volume is 3.0 L and the temperature is 200 K.  The new pressure is 2.0 atm.

If we consider the temperature is constant, then new volume must be 1.5 L since the pressure is doubled and we know that volume is inversely proportional to the pressure.

So, as the pressure is doubled, the volume will be halved means it will decrease from 3.0 L to 1.5 L.

First statement is not correct since it says the new volume will be 6.0 L while temperature is kept constant.

If the volume is kept constant, the temperature must be doubled as the pressure has also doubled. So, new temperature will be 400 K.

second statement is also not correct as it says, the final temperature is 100 K, while volume is kept constant.

Third statement is also not correct as we already have seen that the new volume will be 1.5 L, while the temperature is kept constant.

Hence, the only and only correct statement is fourth as the final temperature will be 400 K(double of initial 200 K), while the volume is kept constant.

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Answer:

Because your body has built-in resistance to certain gases, no matter the size of the gas cloud.

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2 years ago
You have 2.7 moles of carbon. How many atoms do you have?
Gelneren [198K]

Answer:

1.63 × 10²⁴ atoms.

Explanation:

To calculate the number of atoms (N) contained in 2.7moles of carbon, we multiply the number of moles (n) by Avogadro's number (6.02 × 10²³).

That is, N = n × nA

Where;

N = number of atoms

n = number of moles (mol)

nA = Avogadro's numbe

N = 2.7 × 6.02 × 10²³

N = 16.254 × 10²³

N = 1.63 × 10²⁴ atoms.

Hence, there are 1.63 × 10²⁴ atoms in 2.7moles of Carbon.

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It is required to prepare 1250 kg of a solution composed of 12 wt.% ethanol and 88 wt.% water. Two solutions are available, the
bekas [8.4K]

Answer:

437.5 kg of first solution and 812.5 kg of second solution should be mixed to get desired solution.

Explanation:

Let the mass of the first solution be x and second solution be y.

Amount solution required = 1250 kg

x + y = 1250 kg....[1]

Percentage of ethanol in required solution = 12% of 1250 kg

Percentage of ethanol in solution-1 = 5% of x

Percentage of ethanol in required solution = 25% of y

5% of x +  25% of y =12% of 1250 kg

\frac{5}{100}\times x+\frac{25}{100}y=\frac{12}{100}\times 1250 kg

x + 5y = 3000 kg...[2]

Solving [1] and [2] we :

x = 437.5 kg   , y =  812.5 kg

437.5 kg of first solution and 812.5 kg of second solution should be mixed to get desired solution.

8 0
3 years ago
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