Answer:
0.0745 mole of hydrogen gas
Explanation:
Given parameters:
Number of H₂SO₄ = 0.0745 moles
Number of moles of Li = 1.5107 moles
Unknown:
Number of moles of H₂ produced = ?
Solution:
To solve this problem, we have to work from the known specie to the unknown one.
The known specie in this expression is the sulfuric acid, H₂SO₄. We can compare its number of moles with that of the unknown using a balanced chemical equation.
Balanced chemical equation:
2Li + H₂SO₄ → Li₂SO₄ + H₂
From the balanced equation;
Before proceeding, we need to obtain the limiting reagent. This is the reagent whose given proportion is in short supply. It determines the extent of the reaction.
2 mole of Li reacted with 1 mole of H₂SO₄
1.5107 mole of lithium will react with
= 0.7554mole of H₂SO₄
But we were given 0.0745 moles,
This suggests that the limiting reagent is the sulfuric acid because it is in short supply;
since 1 mole of sulfuric acid produced 1 mole of hydrogen gas;
0.0745 mole of sulfuric acid will produce 0.0745 mole of hydrogen gas
Answer:
A. 35Cl1-
Explanation:
Chlorine needs 1 more electron to have full octet thus will take 1 electron and possess a -1 charge.
potassium reacts the most vigorously.
Answer:
2-butanone = 72.11 g/mol (option F)
Propyl acetate = 102.13 g/mol (option C)
4-methyl-2-pentanone = 100.16 g/mol (option D)
Butyl acetate = 116.16 g/mol (option B)
Methanol = 32.04 g/mol (option E)
Ethanol = 46.07 g/mol (option A)
Explanation:
Step 1: Data given
Molar mass of C = 12.01 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16.00 g/mol
Step 2:
2-butanone = C4H8O
⇒ 4*12.01 + 8*1.01 + 16.00 = 72.11 g/mol (option F)
Propyl acetate = C5H10O2
⇒ 5*12.01 + 10*1.01 + 2*16.00 = 102.13 g/mol (option C)
4-methyl-2-pentanone = C6H12O
⇒ 6*12.01 + 12*1.01 + 16.00 = 100.16 g/mol (option D)
Butyl acetate = C6H12O2
⇒ 6*12.01 + 12*1.01 + 2*16.00 = 116.16 g/mol (option B)
Methanol = CH3OH = CH4O
⇒ 12.01 + 4*1.01 + 16.00 = 32.04 g/mol (option E)
Ethanol = C2H5OH = C2H6O
⇒ 2*12.01 + 6*1.01 + 16.00 = 46.07 g/mol (option A)