Answer: -
3.3° C
Explanation: -
Mass of water m = 180.5 g
Energy released as heat Q = 2494 J
Specific heat is defined as the heat required to raise the temperature of the unit mass of a given substance by 1 C.
Specific heat of water Cp = 4.184 (J/g)⋅∘C
Using the formula
Q = m x Cp x ΔT
We get temperature change ΔT = Q / (m x Cp)
= 2494 J / ( 180.5 g x 4.184 (J/g)⋅∘C
= 3.3° C
Thus the temprature change, (ΔT), of the wateris 3.3 °C if 180.5 g of water sat in the copper pipe from part A, releasing 2494 J of energy to the pipe
Answer:
hi aria
good morning
Explanation:
Fill the blank honestly
1.Any Nick name for me_____?
2.my special habit_____?
3.if my phone was with u what will u check_____?
4.good thing in me____?
5.bad thing in me_____?
6. Any questions do u want to ask me_____?
7.which color suits me most__?
8.Do u like me(25%,50%,75%,100%)____?
9.who am to u __ ___?
10.any secret do u want to tell me_____?
11.first impression on me_____?
The substance of 2 Naoh contains 6 atoms
Answer:
1.32*10^23 molecules
Explanation:
sucrose formula: C12H22O11
molar mass: 12(12.01)+22(1.01)+11(16.00)=342.34g/mol
75.0 g C12H22O11 * (1 mol C12H22O11)/(342.34g C12H22O11)=0.219 mol C12H22O11
0.219 mol * (6.022*10^23)/mol = 1.32*10^23 molecules (three sig. figures)
