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Rzqust [24]
3 years ago
11

The path followed by a projectile is called its _____.

Physics
2 answers:
aniked [119]3 years ago
6 0

Answer:

Trajectory

Explanation:

Trajectory is the path followed or traced by a projectile.

It follows a parabola shape. That is the shape got in javeline.

xxTIMURxx [149]3 years ago
5 0

The path followed by a projectile is called its <em>trajectory. (C)</em>

In the most common school situation<em> </em>... <u>with</u> gravity but <u>without</u> air resistance, the trajectory of a projectile is the shape of an inverted parabola (nose  pointing up).  That's the result of constant horizontal velocity and accelerated vertical velocity.

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If you hold a permanent magnet the wrong way in an extremely strong magnetic f eld, its magnetization will be permanently revers
Phoenix [80]

Answer: The domain that is aligned with the applied field will grow, while the domain that is oppositely aligned to the magnetic field will shrink, this is because permanent magnets produces their own magnetic field.

4 0
3 years ago
A diver shines a flashlight upward from beneath the water (n=1.33) at a 36.2° angle to the vertical. At what angle does the ligh
horrorfan [7]

Answer:

The flashlight leaves the water at an angle of 51.77°.

Explanation:

if n1 = 1.33 is the refractive index of water and ∅1 is the angle at which the flashlight shine beneath the water, and n2 = 1.0 is the refractive index of air and ∅2 is the angle the flashlight leaves the water.

Then, according to Snell's law :

n1×sin(∅1) = n2×sin(∅2)

sin(∅2) = n1×sin(∅1)/n2

           = (1.33)×sin(36.2)/(1.0)

           = 0.7855055×379

     ∅2 = 51.77°

Therefore, the flashlight leaves the water at an angle of 51.77°.

7 0
4 years ago
Newton’s Second law of Motion (F = ma) is one of the basis of forces and motion. How is it very similar to his First law and why
koban [17]

Answer:

First law can be deduced from second law.

Acceleration may determine the position and velocity of the system.

Explanation:

When net force is zero, the second law is 0 = ma, or the motion is at constant speed. Thus first law establishes that when there are no forces, the object moves at constant speed, so first law is explained by using the second.

If you determine the acceleration of a system, you may use calculus or kinematic equations to determine velocity and position of the particle and determine how it moves. This is very important in mechanics and engineering, for example, for spacecrafts, forensic situations, etc.

4 0
3 years ago
Ques
Amanda [17]

Answer:

When a particle or a system of particles move in a system where no external force acts, then the total linear momentum of the particle system remains constant.

Explanation:

Given data:

Total mass of the skateboarder, m_{1} = 70 \ kg

Mass of the friend, m_{2} = 50 \ kg

Initial velocity of the skateboarder, u_{1} = 3 \ m/s

Initial velocity of the the friend, u_{2} = 0

Let the new velocity of the skateboarder when his friend jumps be v.

From the conservation law of linear momentum,

m_{1}u_{1} + m_{2}u_{2} = (m_{1} + m_{2})v

70 \times 3 + 50 \times 0 = (70 + 50)v

\Rightarrow \ v &= 1.75 \ m/s.

4 0
4 years ago
How would i solve these problems, nobody in my class understands and there is a substitute
DiKsa [7]

1) X-component: 568.5 N, Y-component: 511.9 N

2) The horizontal force is 86.6 N and the resulting acceleration is 0.87 m/s^2

Explanation:

1)

In this first part of the problem, we have to resolve the force into its two components, along the x and the y direction.

The two components are given by:

F_x = F cos \theta\\F_y = F sin \theta

where

F = 765 N is the magnitude of the force

\theta=42.0^{\circ} is the angle of the force with the horizontal

Substituting, we find:

  • Horizontal component: F_x = (765)(cos 42.0^{\circ})=568.5 N
  • Vertical component: F_y = (765)(sin 42.0^{\circ})=511.9 N

2)

First of all, we have to find the horizontal component of the pulling force, which is given by

F_x = F cos \theta

where

F = 100 N is the magnitude of the pulling force

\theta=30.0^{\circ} is the direction of the force with the horizontal

Substituting,

F_x = (100)(cos 30^{\circ})=86.6 N

Now we can find the acceleration of the wagon by using Newton's second law:

F_x = ma_x

where

F_x = 86.6 N is the net force in the horizontal direction

m = 100 kg is the mass of the wagon

a_x is the acceleration in the horizontal direction

Solving for a_x, we find

a_x = \frac{F_x}{m}=\frac{86.6}{100}=0.87 m/s^2

Learn more about vector components:

brainly.com/question/2678571

And about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

5 0
3 years ago
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