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RSB [31]
3 years ago
10

A 26' long painting is how many yards long?

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
8 0
8.667 or 9 yards

hope this helps; all you do is divide it by 3


dsp733 years ago
6 0
There are 3 feet in a yard so 26/3= 8 2/3
For every three feet 26 there is one yard, so it is 8 2/3 yards long.
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Step-by-step explanation:

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Pls pls help <br> Perform the indicated operations.<br> a) 7a/20b<br> b) 7ab/20<br> c) 7/20ab
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Step-by-step explanation:

5( \frac{a + 2}{4b} ) - 2( \frac{a - 1}{10b} ) + 4( \frac{a - 3}{5b} ) \\  \\  \frac{5a + 10 - 2a + 2 + 4a - 12}{20b }  \\  \\  \\  \frac{7a}{20b}

8 0
2 years ago
The rate of growth of profit​ (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati
Alecsey [184]

Answer:

The function is  P(x) =  \frac{1}{2} e^{-x^2} +0.016

Step-by-step explanation:

From the question we are told that

    The rate of growth  is  P'(x) =  xe^{x} - x^2

     The total profit is P(2)  =$25,000

      The time taken to make the profit is x =  2 \ years

         

From the question

     P'(x) =  xe^{-x^2}  is the rate of growth

  Now here x represent the time taken

Now the total profit is mathematically represented as

       P(x) =  \int\limits {P'(x)} \,  =   \int\limits {xe^{-x^2}} \,

So using substitution method

   We have that

                      u =  - x^2

                      du =  2xdx

  So  

        p(x) =  \int\limits {\frac{1}{2} e^{-u}} \, du

       p(x) =  {\frac{1}{2} [ e^{-u}} +c ]

       p(x) =  {\frac{1}{2}  e^{-x^2}} + \frac{1}{2} c      recall  u =  - x^2   and  let  \frac{1}{2} c =  Z

       

At  x =  2 years  

     P(x)  =$25,000

So

       Since the profit rate is in million

    P(x)  =$25,000 = \frac{25000}{1000000} =$0.025 millon dollars

So  

       0.025 =  {\frac{1}{2}  e^{-2^2}} + Z  

=>    Z = 0.025 - {\frac{1}{2}  e^{-2^2}}  

       Z = 0.016  

So the profit function becomes

         P(x) =  \frac{1}{2} e^{-x^2} +0.016

     

       

5 0
3 years ago
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