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jarptica [38.1K]
2 years ago
6

Select the correct answer.

Chemistry
1 answer:
lidiya [134]2 years ago
8 0

Answer:

8.36 g

Explanation:

From;

0.693/t1/2 = 2.303/t log (No/N)

t1/2 = half life of potassium-40

t = age of the sample

No= initial amount of the sample

N= amount of the sample at time t

Substituting values;

0.693/1.3 × 10^9 = 2.303/2.6 × 10^9 log (No/2.10)

5.33 × 10^-10 = 8.86 × 10^-10 log (No/2.10)

5.33 × 10^-10/8.86 × 10^-10 = log (No/2.10)

0.6 = log (No/2.10)

Antilog (0.6) = (No/2.10)

No = 2.10 × Antilog (0.6)

No= 8.36 g

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he required empirical formula based on the data provided is Na2CO3.H2O.

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The term empirical formula refers to the formula of a compound which shows the ratio of each specie present.

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Mass of sodium = 37.07-g

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