How many moles of KOH are measured in thisexperiment? See the volume and molarity information given. 2.How many moles of KOH rea
cted with the amount of Al you used? Refer to the reaction equation in the first few lines of the experiment.3.How many moles of KOH were left over?
1 answer:
Answer:
0.022 moles of potassium hydroxide reacted with Aluminum and 0.013 moles of potassium hydroxide were left over.
Explanation:
2Al(s) + 2KOH(aq) + 6H2O(l) → 2KAl(OH)4(aq) + 3H2(g)
First we obtain the amount in moles of aluminum added in line with the mass of aluminum to be added in the experimental procedure. This shows us that aluminum metal is the limiting reactant.
Secondly we obtain the amount of KOH in 25mL of 1.4M KOH solution(see attached image). This gives the amount of KOH availiable for reaction.
2 moles of Aluminum metal reacts with 2 moles of KOH according to the balanced reaction equation. Hence 0.022 moles of aluminum will react with 0.022 moles of KOH.
The amount of KOH left unreacted is 0.035-0.022= 0.013 moles of KOH.
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Answer:
The correct answer is: X is nitrogen dioxide, and Y is a metal oxide
Explanation:
Combustion of compound of containing nitrogen and metal will give nitrogen dioxide and metal oxide as product. During combustion reaction a compound reacts with oxygen in order to yield oxides of elements present in the compound.
The general equation is given as:
Hence, the correct answer is :X is nitrogen dioxide, and Y is a metal oxide.
This is an incomplete question, here is a complete question and an image is attached below.
The following diagrams represent mixtures of NO(g) and O₂(g). These two substances react as follows:
It has been determined experimentally that the rate is second order in NO and first order in O₂.
Based on this fact, which of the following mixtures will have the fastest initial rate?
The mixture (1). The mixture (2). The mixture (3).
Answer : The mixture 1 has the fastest initial rate.
Explanation :
The given chemical reaction is:
The rate law expression is:
Now we have to determine the number of molecules of
In mixture 1 : There are 5 and 4
molecules.
In mixture 2 : There are 7 and 2
molecules.
In mixture 3 : There are 3 and 5
molecules.
Now we have to determine the rate law expression for mixture 1, 2 and 3.
The rate law expression for mixture 1 is:
The rate law expression for mixture 2 is:
The rate law expression for mixture 3 is:
Hence, the mixture 1 has the fastest initial rate.
