Particles will have more energy and will vibrate really fast.
(Hope this helps)
The answer for the following problem is mentioned below.
<u><em>Therefore volume occupied by methane gas is 184.78 × 10^-3 liters </em></u>
Explanation:
Given:
mass of methane(
) = 272 grams
pressure (P) = 250 k Pa =250×10^3 Pa
temperature(t) = 54°C =54 + 273 = 327 K
Also given:
R = 8.31JK-1 mol-1 ,
Molar mass of methane(
) = 16.0 grams
We know;
According to the ideal gas equation,
<u><em>P × V = n × R × T</em></u>
here,
n = m÷M
n =272 ÷ 16
<u><em>n = 17 moles</em></u>
Therefore,
250×10^3 × V = 17 × 8.31 × 327
V = ( 17 × 8.31 × 327 ) ÷ ( 250×10^3 )
V = 184.78 × 10^-3 liters
<u><em>Therefore volume occupied by methane gas is 184.78 × 10^-3 liters </em></u>
<u><em></em></u>
<u><em></em></u>
<u><em></em></u>
<u><em></em></u>
<u><em></em></u>
Answer:
The correct answer is - 29.45 / 100 x 25.6 = 7.5392 grams
Explanation:
It is given in the question that in 100 gms of CaSO4 there are 29.45 grams of Ca present and there is 25.6 gram of total CaSO4 sample present, So, to calculate the exact value of calcium in this given sample is:
mass of Ca = total amount of sample*percentage of calcium in sample /100
M of Ca =25.6*29.45/100
M of Ca = 7.5392 grams
Thus, the correct procedure is given by 29.45 / 100 x 25.6 = 7.5392 grams
The answer is
a symmetrical molecule.
Converting temperature of 68°F to °C gives 20 °C.
Converting temperature of 68°F to K gives 293 K.
<h3>What is temperature conversion?</h3>
Temperature conversion is the process of converting the measurement units of the temperature recorded in a particular unit to another unit.
The various units of Temperature include;
- degree Celsius
- degree Fahrenheit
- degree Kelvin
Temperature is measured with thermometer and it records the hotness or coldness of a body.
<h3>Converting 68°F to °C</h3>
F = 1.8C + 32
(F - 32/1.8) = C
(68 - 32) / 1.8 = C
20 ⁰C = 68 ⁰F
<h3>Converting 20°C to K</h3>
0 °C = 273 K
20 °C = 273 + 20 = 293 K
Learn more about temperature conversion here: brainly.com/question/23419049
#SPJ1