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Aliun [14]
3 years ago
15

A chemical reaction occurs between Calcium, Oxygen, and Chlorine. The reaction is demonstrated:

Chemistry
2 answers:
ad-work [718]3 years ago
8 0

Answer:

D.

Double replacement, CaO + Cl2O

Explanation:

DaniilM [7]3 years ago
8 0

Answer:

Double Replacement, Ca0 + CI20

Explanation:

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Why does neon have a smaller atomic radius than lithium?
ladessa [460]
Neon has a smaller atomic radius do it having less of an electron shield. Also the more protons an element has the tighter it is held together making it smaller.
4 0
3 years ago
Boyle's Law expresses the pressure-volume
Colt1911 [192]

Answer:

\large \boxed{\text{175. atm}}

Explanation:

Data:

p₁ = 1.00 atm; V₁ = 350.      L

p₂ = ?;             V₂ =     2.00 L

Calculation:

\begin{array}{rcl}p_{1}V_{1} & = & p_{2}V_{2}\\\text{1.00 atm} \times \text{350. L} & = & p_{2} \times\text{2.00 L}\\\text{350. atm} & = & 2.00p_{2}\\p_{2} & = & \dfrac{\text{350. atm}}{2.00}\\\\& = &\textbf{175. atm}\\\end{array}\\\text{It would take a pressure of $\large \boxed{\textbf{175. atm}}$ to compress the gas.}

8 0
3 years ago
If you have 3.54 g of H2, how many grams of NH3 can be produced?
morpeh [17]
3.54g H2 means you have 3.54 / 2  = 1.77 moles of H2, which means you have 1.77*2 = 3.54 moles of H atom.

Since 1 mole of NH3 has 3 moles of H, so you can produce 3.54 / 3 moles of NH3, which is (3.54/3) * (12+3) = 17.7 grams
5 0
3 years ago
What is the ratio by mass of oxygen to carbon when 32 g of oxygen combine with 12 g of carbon?
Mrac [35]
CO_2
1:2
32gO(1molO/16gO)=2molO
12gC(1molC/12gC)=1molC

4 0
4 years ago
Titration of 0.824 g of potassium hydrogen phthalate required 38.314 g of naoh solution to reach the end point detected by pheno
melamori03 [73]

1.062 mol/kg.

<em>Step 1</em>. Write the balanced equation for the neutralization.

MM = 204.22 40.00

KHC8H4O4 + NaOH → KNaC8H4O4 + H2O

<em>Step 2</em>. Calculate the moles of potassium hydrogen phthalate (KHP)

Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)

= 4.035 mmol KHP

<em>Step 3</em>. Calculate the moles of NaOH

Moles of NaOH = 4.035 mmol KHP × (1 mmol NaOH/(1 mmol KHP)

= 4.035 mmol NaOH

<em>Step 4</em>. Calculate the mass of the NaOH

Mass of NaOH = 4.035 mmol NaOH × (40.00 mg NaOH/1 mmol NaOH)

= 161 mg NaOH

<em>Step 5</em>. Calculate the mass of the water

Mass of water = mass of solution – mass of NaOH = 38.134 g - 0.161 g

= 37.973 g

<em>Step 6</em>. Calculate the molal concentration of the NaOH

<em>b</em> = moles of NaOH/kg of water = 0.040 35 mol/0.037 973 kg = 1.062 mol/kg

3 0
4 years ago
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