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zavuch27 [327]
3 years ago
15

An object is 12 m long, 0.65 m wide, and 13 cm high. Calculate the volume of this object.

Physics
1 answer:
ziro4ka [17]3 years ago
6 0

The volume corresponds to the measure of the space occupied by a body. From the given dimensions we can intuit that we are looking to find the Volume of an Cuboid, that is, an orthogonal rectangular prism, whose faces form straight dihedral angles.

Mathematically the volume of this body is given as

V = lWh

Where,

L = Length

W = Width

H = High

V = (12)(0.65)(13*10^{-2})

V = 1.014m^3

Note: The value given for the height was in centimeters, so it was transformed to meters.

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Answer:

Rectangular path

Solution:

As per the question:

Length, a = 4 km

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In order to minimize the cost let us denote the side of the square bottom be 'a'

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Let the height of the bin be 'h'

Therefore the total area, A_{t} = 4ah

The cost is:

C = 2sh

Volume of the box, V = a^{2}h = 4^{2}\times 2 = 128            (1)

Total cost, C_{t} = 2a^{2} + 2ah            (2)

From eqn (1):

h = \frac{128}{a^{2}}

Using the above value in eqn (1):

C(a) = 2a^{2} + 2a\frac{128}{a^{2}} = 2a^{2} + \frac{256}{a}

C(a) = 2a^{2} + \frac{256}{a}

Differentiating the above eqn w.r.t 'a':

C'(a) = 4a - \frac{256}{a^{2}} = \frac{4a^{3} - 256}{a^{2}}

For the required solution equating the above eqn to zero:

\frac{4a^{3} - 256}{a^{2}} = 0

\frac{4a^{3} - 256}{a^{2}} = 0

a = 4

Also

h = \frac{128}{4^{2}} = 8

The path in order to minimize the cost must be a rectangle.

8 0
3 years ago
What is the speed of an object at rest
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Explanation:

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Answer:

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