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tatyana61 [14]
3 years ago
10

In the oxygen cycle, oxygen is

Physics
1 answer:
dlinn [17]3 years ago
7 0

Answer:

4.) added to the atmosphere by photosynthesis and removed by cellular respiration and combustion.

Explanation:

  • The atmospheric cycle is a biogeochemical cycle and is a transition between the oxidation state in ions, oxides, and molecules. The largest reservoir on the earth for oxygen island or lithosphere.
  • The crust and mantle together make up 99.5% of oxygen by volume. The rest is found in the air that 21%, 22% in the biosphere, and 33% in the hydrosphere.
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A hot air balloon lifts 50 meters vertically into the air and then comes back down. What are the displacement and distance of th
Marysya12 [62]

Given that a hot air balloon lifts 50 meters vertically into the air and then comes back down.

The displacement is the distance covered in a specific direction.

When the balloon is going up, the displacement is positive. and when the balloon is coming down, the displacement is negative.

The total displacement = 50 - 50 = 0

The distance is a measurement of length between to different points or position.

For distance, there is no need to consider direction. There is no consideration for positive or negative signs

While the distance = 50 + 50 = 100 meters

Therefore, the correct answer is C

That is, The displacement is zero and the distance is 100 meters

Learn more on ; brainly.com/question/24662122

4 0
2 years ago
Read 2 more answers
How much energy is needed to perform 300 J of work?
4vir4ik [10]
I think this is the answer hope it helps

3 0
3 years ago
If a 10. m3 volume of air (acting as an ideal gas) is at a pressure of 760 mm and a temperature of 27 degrees Celsius is taken t
kow [346]
We know, the ideal gas equation, 
P1V1 / T1 = P2V2 / T2

Here, P1 = 760 mm
V1 = 10 m3
T1 = 27 + 273 = 300 K

P2 = 400 mm Hg
T2 = -23 + 273 = 250 K

Substitute their values, 
760*10 / 300 = 400 * V2 / 250
25.33 * 250 = 400 * V2
V2 = 6333.333/ 400
V2 = 15.83

In short, Your Answer would be approx. 15.83 m3

Hope this helps!
7 0
3 years ago
Two cars are traveling along a straight line in the same direction, the lead car at 25 m/s and the other car at 35 m/s. At the m
Phoenix [80]

Answer:

a. t_1=12.5\ s

b. a_2=-13.61\ m.s^{-2}  must be the minimum magnitude of deceleration to avoid hitting the leading car before stopping

c. t_2=2.5714\ s is the time taken to stop after braking

Explanation:

Given:

  • speed of leading car, u_1=25\ m.s^{-1}
  • speed of lagging car, u_{2}=35\ m.s^{-1}
  • distance between the cars, \Delta s=45\ m
  • deceleration of the leading car after braking, a_1=-2\ m.s^{-2}

a.

Time taken by the car to stop:

v_1=u_1+a_1.t_1

where:

v_1=0 , final velocity after braking

t_1= time taken

0=25-2\times t_1

t_1=12.5\ s

b.

using the eq. of motion for the given condition:

v_2^2=u_2^2+2.a_2.\Delta s

where:

v_2= final velocity of the chasing car after braking = 0

a_2= acceleration of the chasing car after braking

0^2=35^2+2\times a_2\times 45

a_2=-13.61\ m.s^{-2} must be the minimum magnitude of deceleration to avoid hitting the leading car before stopping

c.

time taken by the chasing car to stop:

v_2=u_2+a_2.t_2

0=35-13.61\times t_2

t_2=2.5714\ s  is the time taken to stop after braking

7 0
3 years ago
Where are globular clusters located in the milky way?.
mel-nik [20]

Answer:

Globular star clusters are located in the great spherical halo.

Explanation:

Hope this helps! :)

8 0
2 years ago
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