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RideAnS [48]
2 years ago
12

The tau neutrino, the muon neutrino, and the electron neutrino are all.

Physics
1 answer:
Lina20 [59]2 years ago
5 0

Tau neutrino, the muon neutrino, and the electron neutrino are all the types of neutrino.

<h3>What is a neutrino?</h3>

The term neutrino refers to a type of subatomic particle that is very similar to an electron. The difference between the  neutrino and the electron is that the neutrino has no charge.

Tau neutrino, the muon neutrino, and the electron neutrino are all the types of neutrino.

Learn more about neutrino:brainly.com/question/13790391

#SPJ1

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If you subtract vector 3.7 cm at 45° North of East from vector 4.5 cm at 57° West of North using a scale drawing, what is the re
Gelneren [198K]

The resultant vector is 5.2 cm at a direction of 12⁰ west of north.

<h3>Resultant of the two vectors</h3>

The resultant of the two vectors is calculated as follows;

R = a² + b² - 2ab cos(θ)

where;

  • θ is the angle between the two vectors =  45° + (90 - 57) = 78⁰
  • a is the first vector
  • b is the second vector

R² = (3.7)² + (4.5)² - (2 x 3.7 x 4.5) cos(78)

R² = 27.02

R = 5.2 cm

<h3>Direction of the vector</h3>

θ = 90 - 78⁰

θ = 12⁰

Thus, the resultant vector is 5.2 cm at a direction of 12⁰ west of north.

Learn more about resultant vector here: brainly.com/question/28047791

#SPJ1

3 0
1 year ago
When velocity is graphed with respect to time, what does the area under
Juliette [100K]

Answer:

the answer is D

Explanation:

Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object.

4 0
3 years ago
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Gravity is a force. <br> True <br> False
Ratling [72]
The answer is true. Gravity is the force that keeps us all on the ground.
7 0
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Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field
Katyanochek1 [597]

Complete question:

Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field strength  at the midpoint between the two rings ?

Answer:

The electric field strength at the mid-point between the two rings is zero.

Explanation:

Given;

diameter of each ring, d = 10 cm = 0.1 m

distance between the rings, r = 21.0 cm = 0.21 m

charge of each ring, q = 40 nC = 40 x 10⁻⁹ C

let the midpoint between the two rings = x

The electric field strength  at the midpoint between the two rings is given as;

E_{mid} = E_{right} +E_{left}\\\\E_{right}  = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } \\\\E_{leftt}  = -\ \frac{KQ}{(x^2 + r^2)^\frac{2}{3} }\\\\E_{mid} = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} }  - \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } = 0

Therefore, the electric field strength at the mid-point between the two rings is zero.

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3 years ago
What is the unit of measurement for expressing the intensity of sound
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Decibel - the decibel is a relative unit of measurement equal to one 10th of a bel
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