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Alex787 [66]
3 years ago
13

This is the chemical formula for nickel tetracarbonyl (a powerfully poisonous liquid used in nickel refining):nico4a chemical en

gineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. how many moles of oxygen are in the sample?round your answer to 2 significant digits.
Chemistry
1 answer:
lesya [120]3 years ago
8 0

Answer : There are 7.0 moles of oxygen in the formula.

Explanation :

The chemical formula of nickel tetracarbonyl is Ni(CO)₄.

We can see that there are 4 carbon atoms and 4 oxygen atoms which together form 4 carbonyl (CO) groups.

Therefore the mole ratio of C to O is 1 : 1.

Let us use this as a conversion factor to find moles of oxygen.

We have 7.0 moles of carbon in the formula.

The moles of O can be calculated as,

7 mol C \times \frac{1 mol O}{1 mol C} = 7.0 mol O

There are 7.0 moles of oxygen in the formula.

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fiasKO [112]
<h3>Answer:</h3>

1.2 × 10⁻⁸ mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 7.2 × 10¹⁵ atoms Pb

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 7.2 \cdot 10^{15} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})
  2. [DA] Multiply/Divide [Cancel out units]:                                                            \displaystyle 1.19562 \cdot 10^{-8} \ mol \ Pb

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.19562 × 10⁻⁸ mol Pb ≈ 1.2 × 10⁻⁸ mol Pb

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