Ask question

Ask question

All categories

2 years ago

15

Silicon is in the same group of the Periodic Table as carbon. The compound

1 answer:

iragen [17]2 years ago

4 0

Answer:

SiH

Explanation:

The symbol for Silicon is Si, and the symbol for Hydrogen is H. There is no need for extra characters in the name.

You might be interested in

Decide which element probably forms a compound with chlorine that has a chemical formula most and least similar to the chemical

valentinak56 [21]

Answer:

phosphorus - least similar to barium

beryllium - most similar to barium

Explanation:

The formula of the chloride formed between barium and chlorine is BaCl2.

Barium is a metallic element and has the valency of +2. Beryllium is also a group two metal with a valency of +2. Hence the compound formed between beryllium and chlorine is BeCl2

Phosphorus is a nonmetal and forms a completely different chloride from BaCl2. The chloride of phosphorus is PCl5 and PCl3. These are least similar to BaCl2

6 0

2 years ago

Please help It’s due today

nikitadnepr [17]

Answer:

Conductors

Explanation:

6 0

2 years ago

Read 2 more answers

Any kind of help would be nice :)

alina1380 [7]

Answer:

1st page, number a-ENergy is added or absorbed

I cant see the answers on the 2nd page

Explanation:

8 0

2 years ago

Read 2 more answers

C-12 and C-13 are naturally-occurring isotopes of the element carbon. C-12 occurs 98.88% of the time and C-13 occurs 1.108% of t

Veseljchak [2.6K]

Answer:

c) (12×0.9889) + (13×0.01108)

Explanation:

Given data:

Percentage of C-12 = 98.89%

Percentage of C-13 = 1.108%

Atomic mass = ?

Solution:

98.89/100 = 0.9889

1.108/ 100 = 0.01108

Atomic mass = (12×0.9889) + (13×0.01108)

Atomic mass = (11.8668 + 0.144034)

Atomic mass = 12.01084

6 0

2 years ago

A 8.00 L tank at 26.9 C is filled with 5.53 g of dinitrogen difluoride gas and 17.3 g of sulfur hexafluoride gas. You can assume

pshichka [43]

Answer:

mole fraction of N_2 O = 0.330

mole of fraction SF_4 = 0.669

PRESSURE OF N_2 O = 39127.053 Pa

pressure of SF_4 = 792126.36

Total pressure = 118253.413 Pa

Explanation:

Given data:

volume of tank 8 L

Weight of dinitrogen difluoride gas 5.53 g

weight of sulphur hexafluoride gas 17.3 g

Amount of $N_2 O = \frac{5.53}{14*2 + 16} = 0.1256 mol$

amount of $SF_4 = \frac{17.3}{32.1 + 19*4} = 0.254 mol$

mole fraction of $N_2 O = \frac{0.1256}{0.1256 + 0.254} = 0.330$

mole of fraction $SF_4 = \frac{0.254}{0.1256 + 0.254} = 0.669$

PV = nRT

P of N_2 O $= \frac{0.1256 *8.31 (273 + 26.9}{0.008} = 39127.053 Pa$

mole of SF_4 $=\frac{0.254 *8.31*(273+26.9)}{.008} = 79126.36 Pa$

Total pressure = 39127.053 + 79126.36 = 118253.413 Pa

6 0

2 years ago