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BlackZzzverrR [31]
3 years ago
11

A very long nonconducting cylinder of diameter 10.0 cm carries charge distributed uniformly over its surface. Each meter of leng

th carries +5.50 µC of charge. A proton is released from rest just outside the surface. How far will it be from the SURFACE of the cylinder when its speed has reached 2550 km/s? (k = 1/4πε0 = 8.99 × 10^9 N.m^2/C2, e = 1.60 × 10^-19 C, m proton = 1.67 x 10^-27 kg)

Physics
1 answer:
Murrr4er [49]3 years ago
7 0

Answer:

Explanation:

The concept of electric field, force acting on proton is applied and appropriate derivations were made to calculate the distance from the surface as shown in the attached file.

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