Answer:
2.23 Hz
Explanation:
From the attached diagram below; there exists a diagrammatic representation of the equilibrium position of the cylinder.
The equilibrium position of the spring is expressed as:
mg = K
where;
m = mass of the object
g = acceleration due to gravity
K = spring constant
= static deflection of the string
Given that:
m = 30 kg
g = 9.81 m/s²
= 50 mm = 50 × 
= 0.05 m
Then;
From here; let us find the angular velocity which will be needed to determine the natural frequency aftewards.
The angular velocity of the cylinder can be expressed by the formula:
Finally; the natural frequency 
can be calculated by using the equation
= 2.229305729
≅ 2.23 Hz
Thus; the resulting natural frequency of the vertical vibration of the cylinder = 2.23 Hz
Answer: y = yo + Vyot + ayt = =2ay y− yo . 5. vy. 2. −voy. 2. =−2 g y− yo
Explanation: since both the displacement and acceleration are negative, they cancel each other when divided, so the result is positive. ... As you can see, as the height displacement (height) increases, the longer it takes for the robocopter to fall.
Answer:
the phase difference is 1.26 radian
Solution:
As per the question:
Distance, d = 2 m
Distance from the other speaker, d' = 2.1 m
Frequency, f = 680 Hz
Speed of sound, v = 340 m/s
Now,
To calculate the phase difference, 
:
Path difference, 
For the wavelength:
where
c = speed of light in vacuum
= wavelength
Now,
Now,
Phase difference, 
