A particle has velocity v⃗1 v → 1 as it accelerates from 1 to 2. What is its velocity vector v⃗2 v → 2 as it moves away from poi
nt 2 on its way to point 3?
1 answer:
Answer:
The velocity of the particle will be downward.
Explanation:
Given that,
The velocity of a particle is v₁. It is accelerated from 1 to 2.
If it moves away from point 2 on its way then
We need to find the velocity of particle
According to figure,
A particle moves downward from 1 to 2 with the velocity v₁ and after that the particle moves downward from 2 to 3 with the velocity v₂.
Hence, The velocity of the particle will be downward.
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Answer:
24,187.04 J ≈ 24,200 J
Explanation:
mass (m) = 544 kg
initial speed (u) = 6.75 m/s
final speed (v) = 15.2 m/s
change in height (Δh) = -14 m (negative sign is because there is a decrease in height )
acceleration due to gravity (g) = 9.8 m/s^{2}
How much work was done on the raft by non conservative forces?
work done = change in energy of the system = change in kinetic energy + change in potential energy
work done = () + (mgΔh)
work done = () + (544 x 9.8 x (-14))
work done = 50449.76 - 74,636.8
work done = 24,187.04 J ≈ 24,200 J