Answer:
Total impulse =  = Initial momentum of the car
 = Initial momentum of the car
Explanation:
Let the mass of the car be 'm' kg moving with a velocity 'v' m/s. 
The final velocity of the car is 0 m/s as it is brought to rest.
Impulse is equal to the product of constant force applied to an object for a very small interval. Impulse is also calculated as the total change in the linear momentum of an object during the given time interval.
The magnitude of impulse is the absolute value of the change in momentum.

Momentum of an object is equal to the product of its mass and velocity.
So, the initial momentum of the car is given as:

The final momentum of the car is given as:

Therefore, the impulse is given as:

Hence, the magnitude of the impulse applied to the car to bring it to rest is equal to the initial momentum of the car.
 
        
             
        
        
        
Answer:
Refer to the attachment for solution (1). 
<h3><u>Calculating time taken by it to stop (t) :</u></h3>
By using the second equation of motion, 
→ v = u + at
- v denotes final velocity
- u denotes initial velocity
- t denotes time
- a denotes acceleration
→ 0 = 5 + (-5/6)t
→ 0 = 5 - (5/6)t
→ 0 + (5/6)t = 5
→ (5/6)t = 5
→ t = 5 ÷ (5/6) 
→ t = 5 × (6/5) 
→ t = 6 seconds
→ Time taken to stop = 6 seconds
 
        
             
        
        
        
Answer:
Explanation:
Given
Initial Intensity of light is S
when an un-polarized light is Passed through a Polarizer then its intensity reduced to half.
When it is passed through a second Polarizer with its transmission axis 

here 


When it is passed through third Polarizer with its axis  to first but
 to first but  to second thus
 to second thus 



When middle sheet is absent then Final Intensity will be zero                     
 
        
             
        
        
        
Answer: 
Explanation:
Given
Capacitance 
Resistance 
Inductance 
In LCR circuit, current is maximum at resonance frequency i.e.
 
Insert the values

Also, frequency is given by 

