A. The acceleration of the ball while it is in flight?
magnitude is 0 m/s² (magnitude is zero)
B. The velocity of the ball when it reaches its maximum height is 0 m/s (magnitude is zero)
C. The initial velocity of the ball 8.036 m/s upward
D. The maximum height reached by the ball is 3.29 m
<h3>A. How to determine the acceleration in the flight</h3>
Considering that the ball came to rest after 1.64s, it means the entire acceleration of the flight is zero as the ball was not moving in any form again.
<h3>B. How to determine the velocity at maximum height</h3>
At maximum height, the velocity of the ball is zero as it no longer has magnitude to keep going upwards. Hence the ball begins to ball down.
<h3>C. How to determine the initial velocity</h3>
- Acceleration due to gravity (g) = 9.8 m/s²
- Final velocity (v) = 0 m/s
- Time of flight (T) = 1.64 s
- Time to reach maximum height (t) = T / 2 = 1.64 / 2 = 0.82 s
- Initial velocity (u) =?
v = u - gt (since the ball is going against gravity)
0 = u - (9.8 × 0.82)
0 = u - 8.036
Collect like terms
u = 0 + 8.036
u = 8.036 m/s upward
<h3>D. How to determine the maximum height reached by the ball</h3>
- Time to reach maximum height (t) = T / 2 = 1.64 / 2 = 0.82 s
- Acceleration due to gravity (g) = 9.8 m/s²
- Maximum height (h)
h = ½gt²
h = ½ × 9.8 × 0.82²
h = 3.29 m
Learn more about motion under gravity:
brainly.com/question/20385439
#SPJ1
Answer:
more than 90%
Explanation:
In the unknown liquid the buoyant force and weight relation is
It can be seen that if the density decreases the buoyant force decreases.
If the object is already 90% submerged in water then, if the other liquid has density less than that of water the object will be submerged more than 90%.
Answer:
v = 7.67 m/s
Explanation:
The equation for apparent weight in the situation of weightlessness is given as:
Apparent Weight = m(g - a)
where,
Apparent Weight = 360 N
m = mass passenger = 61.2 kg
a = acceleration of roller coaster
g = acceleration due to gravity = 9.8 m/s²
Therefore,
360 N = (61.2 kg)(9.8 m/s² - a)
9.8 m/s² - a = 360 N/61.2 kg
a = 9.8 m/s² - 5.88 m/s²
a = 3.92 m/s²
Since, this acceleration is due to the change in direction of velocity on a circular path. Therefore, it can b represented by centripetal acceleration and its formula is given as:
a = v²/r
where,
a = centripetal acceleration = 3.92 m/s²
v = speed of roller coaster = ?
r = radius of circular rise = 15 m
Therefore,
3.92 m/s² = v²/15 m
v² = (3.92 m.s²)(15 m)
v = √(58.8 m²/s²)
<u>v = 7.67 m/s</u>
Answer:
The speed of proton when it emerges through the hole in the positive plate is 
.
Explanation:
Given that,
A parallel-plate capacitor is held at a potential difference of 250 V.
A A proton is fired toward a small hole in the negative plate with a speed of, 
We need to find the speed when it emerges through the hole in the positive plate. It can be calculated using the conservation of energy as :
So, the speed of proton when it emerges through the hole in the positive plate is .
