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damaskus [11]
3 years ago
9

Please help this is physics!!!

Physics
1 answer:
larisa [96]3 years ago
8 0
I’m pretty sure u have it right
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Mickey walks Pluto 4 miles North to the dog park. Mickey finds beautiful
yanalaym [24]
Answer is 12 milesBecause yeah
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3 years ago
A small car and a large heavier bus are traveling at the same speed. Which has more momentum?
lions [1.4K]

Answer:

small car since they weigh less than a bus

Explanation:

7 0
3 years ago
D. If a dog has a mass of 12 kg, what is its weight on Neptune?<br> 11.7N/kg
steposvetlana [31]

Answer:

133.8 N

Explanation:

Recall that the acceleration of gravity in Neptune is estimated as 11.15 m/s^2

Therefore, the weight of the dog on this planet would be:

Weight = mass x acceleration of gravity = 12 kg x 11.15 m/s^2 = 133.8 N

4 0
3 years ago
____ can lift the 403,342 ton pioneering spirit crane vessel 10 meters in 30 seconds as if it was a cork. This about 36 GJ if wo
azamat

Answer:   <u>Trough </u> can lift the 403,342 ton pioneering spirit crane vessel 10 meters in 30 seconds as if it was a cork. This about 36 GJ if work and 1 GW of power.

Explanation:

  • Why trough?

Trough is the correct answer because<u> pioneering scale usually abide only on  trough not on the other given options</u>. A long , narrow depression between the waves or ridges is known as a trough. The lower point in the period is the trough.

  • <u>Speed -:</u> Speed is the distance per unit of time that a body moves. It's a quantity scaler that has just magnitude.
  • <u>Wave energy -: </u>The transmission and capture of energy by ocean surface waves is wave energy (or wave power). The energy collected is then used for all sorts of useful work, including the generation of electricity, water desalination, and water pumping.
  • <u>Crest -</u>: A crest point within a cycle on a wave with the highest value of upward displacement. A crest is a point on a surface wave where the medium's displacement is at its height.
  • <u>Amplitude -:</u> The maximum displacement or distance measured from its equilibrium position, moved by a point on a vibrating body or wave, is called amplitude. It is equal to half of the vibration path's length.
  • <u>Period-</u>: The duration T is the time needed to pass a given point for one complete cycle of vibration. The wave length decreases as the frequency of a wave increases.
  • <u>Wavelength-:</u> The distance between two successive crests or troughs of a wave can be described as the wavelength. The frequency is inversely proportional to the wavelength. This implies that the longer the wavelength, the smaller the frequency. Similarly, the shorter the wavelength, the higher the frequency would be.
  • <u>Frequency</u> -: Frequency defines the number of waves in a given amount of time that travel through a fixed location. In the Hertz unit, frequency is normally measured.
  • <u>Information</u> -: A piece of data is a basic fact about the identity or properties of an object, i.e. a portion of its example.
  • <u>Milli -</u>: Milli is known as a merged form meaning 'thousand' (millipede) used in the metric system for unit names equal to one thousandth of the base unit (millimeter) given.

Hence , the answer is <u>TROUGH.</u>

7 0
3 years ago
You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics
spayn [35]

Answer:

v_0 = 3.53~{\rm m/s}

Explanation:

This is a projectile motion problem. We will first separate the motion into x- and y-components, apply the equations of kinematics separately, then we will combine them to find the initial velocity.

The initial velocity is in the x-direction, and there is no acceleration in the x-direction.

On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.

Applying the equations of kinematics in the x-direction gives

x - x_0 = v_{x_0} t + \frac{1}{2}a_x t^2\\63 \times 10^{-3} = v_0t + 0\\t = \frac{63\times 10^{-3}}{v_0}

For the y-direction gives

v_y = v_{y_0} + a_y t\\v_y = 0 -9.8t\\v_y = -9.8t

Combining both equation yields the y_component of the final velocity

v_y = -9.8(\frac{63\times 10^{-3}}{v_0}) = -\frac{0.61}{v_0}

Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.

\tan(\theta) = \frac{v_y}{v_x}\\\tan(177.2^\circ) = -0.0489 = \frac{v_y}{v_0} = \frac{-0.61/v_0}{v_0} = -\frac{0.61}{v_0^2}\\v_0 = 3.53~{\rm m/s}

6 0
3 years ago
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