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damaskus [11]
3 years ago
9

Please help this is physics!!!

Physics
1 answer:
larisa [96]3 years ago
8 0
I’m pretty sure u have it right
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Laura and Elana are discussing how to solve the following problem: "A canary sits 10 m from the end of a 30-m-long clothesline,
horrorfan [7]

Answer:

f=2.236\ Hz

Explanation:

Given:

Length of a rope,l=30\ m

Position of Canary on the rope from one end, l_c=10\ m

Position of Grackle on the rope from another end, l_g=5\ m

Tension in the rope, F_T=200\ N

linear mass distribution on the rope, \mu=0.1\ kg.m^{-1}

We have for the speed of wave on the string:

v^2=\frac{F_T}{\mu}

v^2=\frac{200}{\0.1}

v=44.7\ m.s^{-1}

<em>For canary to be undisturbed we need a node at this location.</em>

<em>Also, at the end close to Canary there must be a node to avoid any change in pattern of vibration.</em>

So,

the distance between Canary and the closer end must be equal to half the wavelength.

\frac{\lambda}{2} =10\ m

\Rightarrow \lambda=20\ m

∴Wavelength of wave to be produced = 20 m. This will give us nodes at the multiples of 10 and anti-nodes at the multiples of 5.

Now, frequency:

f=\frac{v}{\lambda}

f=\frac{44.7}{20}

f=2.236\ Hz

3 0
3 years ago
What is the drawback to use period of pendulum as time standard
Vadim26 [7]

The time period of a simple pendulum depends upon its length and value of'g'at any place. The period of the pendulum of fixed length

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3 years ago
Based on the law of conservation of energy, how can we reasonably improve a machine’s ability to do work?
MrMuchimi

D. Redefine the machine’s system boundaries.

The Law of Conservation of Energy states that energy can't be created not destroyed. Energy, however, can be changed from one form to another. The law applies to isolated systems only. By redefining and expanding the system (including all factors affecting it) , the machine's ability to do work should improve.

7 0
3 years ago
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A 2.0 kg particle moves in a circle of radius 3.1 m. As you look down on the plane of its orbit, the particle is initially movin
Ghella [55]

Answer

given,

L(t) = 10 - 3.5 t

mass of particle = 2 Kg

radius of the circle = 3.1 m

a) torque

    τ = \dfrac{dL}{dt}

    τ = \dfrac{d}{dt}(10 - 3.5 t)

    τ = -3.5 N.m

Particle rotates clockwise as i look down the plane. Hence, its angular velocity is downward.

L decreases the angular acceleration upward. so, net torque is upward.

b) Moment of inertia of the particle

    I = m R^2

    I = 2 x 3.1²

    I = 19.22 kg.m²

    L = I ω

    ω = \dfrac{L}{I}

    ω = \dfrac{10 - 3.5 t}{19.22}

    ω = 0.520 - 0.182 t

  A = 0.52 rad/s             B = -0.182 rad/s²

5 0
3 years ago
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Which option describes the direction of thermal energy transfer in Earth's
Montano1993 [528]

.........

Explanation:

Option B..... ...

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