Answer:
20 N
Explanation:
<em>Newton's second Law of motion</em> law states that If there is a external force acting on an object. Then the rate of change of momentum of that object is directly proportional to the force acting on its.
- the net force acting upon the object <em>(F)</em>
- the mass of the object. <em>(m)</em>
- <em>V </em>Final velocity of the object
- U initial velocity of the object
- mV -Final momentum of the object
- mU - Initial momentum of the object
Due to momentum change of that object, momentum change. We can write the equation bellow this,
F = (mV-mU)/t
When m is constant we can write the above expression like this,
F = m (V-U)/t
There for
(V-U)/t = a ( Rate of change of velocity can be denoted as acceleration )
F = m× a
we can state this in mathematically,
a = F/m
in another representation
F = m*a
Net Force = mass*acceleration
= 10 * 2
= 20 N
object is subjected to a negative acceleration due to the friction.
Answer:
69.66 Joule
Explanation:
mass of bicycle frame, mf = 8.29 kg
mass of wheel, mw = 0.820 kg
radius, r = 0.343 m
velocity, v = 3.6 m/s
There are two wheels in the bicycle.
There are two types of kinetic energy of the system one is kinetic energy of rotation and another is rotational kinetic energy.




K = 69.66 J
Answer: leftover radiation from the big bang
Microwave background radiation is a form of electromagnetic radiation that is present in the whole universe and completely fills it.
Its frequency belongs to the microwaves range and is one of the main demonstrations of the of the Big Bang theory model.
It is important to note the Big Bang occurred 400,000 years before the events related to the microwave cosmic radiation, this means the Big Bang occurred first.
Sorry for the messy handwriting but this is what I got
Answer:
Total mass of combination = 2+3+5 = 10kg.
Acceleration produced = 2m/s^2
hence force =( total mass × acceleration)= (2×10)= 20 N.
Net force on 3kg block = acceleration × mass = (2 × 2 )= 4 N
applied force on 2 kg block = 20N
Force between 2 kg and 3 kg block = (20-4) = 16N. ans
Net force on 3 kg block = 3 × 2 =6N.
Applied force on 3 kg block due to 2 kg block = 16N.
hence, force between 3 kg and 5 kg block = (16-6) = 10N .
answers:-
(a) 20 N
(b) 16N
(c) 10 N