Answer:6.71 m/s
Explanation:
Given
Apple fall from a height of
We need to find the impact speed of apple which can be given by using
where v=final velocity
u=initial velocity
h=Displacement
Assuming initial velocity to be zero
substituting the value we get
Answer:
Explanation:
I think the answer is statement no 3.
Hope it helps.
Answer:
20 hertz of frequency produced.
Explanation:

Here we will find frequency and period should be in second, here given: 0.05 seconds
using the formula:


Answer:
The time it can operate between chargins in minutes is

Explanation:
Given:
,
, 
a). The rotational kinetic energy






b). The power average 0.8kW un range time can be find

Solve to t'


