A woman walks in a straight line with the sun to her right at six o'clock in the morning.
The sun rises East of her, so the woman is walking toward the North pole.
A man walks in a straight line with the sun to his right at six o'clock in the evening.
The sun sets West of him, so the man is walking toward the South pole.
The woman and the man are both walking along lines of constant longitude.
Answer:
a moving object will keep moving if not stopped
the sun being at the center of the solar system
Explanation:
Galileo is known for being the first person make a telescope, there fore being the first person to see that the sun is in the center of the solar system. he also came up with the theory that if something is pushed, it would keep moving until stopped by another force. For example, say you drop your pencil, it keeps falling until it hits the ground. That is exactly what Galileo did in his Leaning Tower of Pisa experiment and found that theory to be true.
Answer:
65.73N
Explanation:
The frictional force is a force that opposes the motion of an object on a flat surface or an inclined surface.
It is always acting up an incline plane .
Since the pipe will tend to roll up the plane, then both the impending force P also known as frictional force and the moving force Fm both will be acting up the plane.
The net force acting up the plane is
Fnet = P + Fm... (1)
The force perpendicular to the plane known as the normal reaction R must be equal to the force acting along the ramp in other to keep the body in equilibrium i.e R = Fnet
If R = W = mgcos (theta)
and Fm = mgsin(theta)
Then mgcos theta = Fnet
mgcos (theta) = P+Fm
mgcos (theta) = P+mgsin(theta)
P = mgcos (theta) - mgsin(theta)... (2)
Given mass = 10kg
g = 9.81m/s
We can get theta from the formula;
µ = Ff/R = wsin theta/wcos theta
µ = sin theta/cos theta
µ = tan(theta)
0.3 = tan (theta)
theta = arctan0.3
theta = 16.7°
P = 10(9.81)cos16.7° - 10(9.81)sin16.7°
P = 98.1(cos16.7°-sin16.7°)
P = 98.1(0.67)
P = 65.73N
The minimum force P required to cause impending motion is 65.73N
Answer:
2.46 eV
Explanation:
It is given that,
The energy of light that fall on the metal = 3.56 eV
The stopping potential of the metal = 1.1 V
We need to find the work function of the metal. It is given by the relation as follows :
W = E-KE ...(1)
Where KE is the kinetic energy of the ejected electron and it is given by :
KE = V×e
= 1.1 eV
Put all the values in formula (1)
W = 3.56 eV - 1.1 eV
= 2.46 eV
Hence, the work function of the metal is 2.46 eV. Hence, the correct option is (c).
