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Naily [24]
4 years ago
12

The chemical elements are arranged in order of increasing atomic number. The rows are called periods and the columns are called

groups.
Physics
1 answer:
Dmitriy789 [7]4 years ago
8 0
The correct answer is: True

Explanation:
Indeed the chemical elements in the periodic table are arranged in terms of their atomic number. They are usually written at the top of the elements in the boxes of the periodic table. Furthermore, in the periodic table, the rows are called the periods and columns are called the groups.
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How much work is done by the force of gravity when the book is released?
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) A cable car at a ski resort carries skiers a distance of 6.8 km. The cable which moves the car is driven by a pulley with diam
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3 years ago
A projectile is launched straight up from a height of 960 feet with an initial velocity of 64 ft/sec. Its height at time t is h(
Natasha2012 [34]

Answer:

a) t=2s

b) h_{max}=1024ft

c) v_{y}=-256ft/s

Explanation:

From the exercise we know the initial velocity of the projectile and its initial height

v_{y}=64ft/s\\h_{o}=960ft\\g=-32ft/s^2

To find what time does it take to reach maximum height we need to find how high will it go

b) We can calculate its initial height using the following formula

Knowing that its velocity is zero at its maximum height

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

0=(64ft/s)^2-2(32ft/s^2)(y-960ft)

y=\frac{-(64ft/s)^2-2(32ft/s^2)(960ft)}{-2(32ft/s^2)}=1024ft

So, the projectile goes 1024 ft high

a) From the equation of height we calculate how long does it take to reach maximum point

h=-16t^2+64t+960

1024=-16t^2+64t+960

0=-16t^2+64t-64

Solving the quadratic equation

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=64\\c=-64

t=2s

So, the projectile reach maximum point at t=2s

c) We can calculate the final velocity by using the following formula:

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

v_{y}=±\sqrt{(64ft/s)^{2}-2(32ft/s^2)(-960ft)}=±256ft/s

Since the projectile is going down the velocity at the instant it reaches the ground is:

v=-256ft/s

5 0
3 years ago
(b) The density of aluminum is 2.70 g/cm3. The thickness of a rectangular sheet of aluminum foil varies
vekshin1

Answer:

(i) 22.48 cm^3

(ii) 1.5 mm

Explanation:

Let t be the average thickness of the sheet.

Given that:

Density of the aluminum sheet is 2.70 g/cm^3

Mass of sheet = 60.7 g

Length of sheet  = 50.0 cm

Width of sheet  = 30.0 cm

(i) Using, Density=Mass/Volume

\Rightarrow \text{Volume}=\frac{\text{Mass}}{\text{Density}}

\Rightarrow \text{Volume}=\frac{60.7}{2.7}=22.48 cm^3

Hence, the volume of the sheet is 22.48 cm^3.

(ii) Now, as this aluminum sheet is in the shape of a cuboid, so the volume of the sheet is

\text{Volume}=\text{Length}\times\text{Width}\times\text{Thickness}

\Rightarrow 22.48=50\times 30 \times w

\Rightarrow w=\frac{22.48}{50\times 30}=0.015 cm

Hence, the average thickness of the sheet is 1.5 mm.

6 0
3 years ago
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