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ASHA 777 [7]
3 years ago
6

Why is blood important

Physics
1 answer:
Margarita [4]3 years ago
5 0

Blood is essential for good health because the body depends on a steady supply of fuel and oxygen to reach its billions of cells. Even the heart couldn't survive without blood flowing through the vessels that bring nourishment to its muscular walls.


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Reading glasses with a power of 1.50 diopters make reading a book comfortable for you when you wear them 1.8 cmcm from your eye.
Vlad1618 [11]

Answer:

The near point is  n =44.8 \ cm

Explanation:

From the question we are told that

   The power is  P  = 1.50

   The  distance from the eye is  k  =  1.8 \ cm

    The distance of the book from the eye is z =  -28 \ cm

Generally the focal length of the glasses is  

       f =  \frac{1}{P}

=>   f =  \frac{1}{1.50 }

=>   f =  0.667 \ m

=>   f =  66.7 \ cm

The object distance is evaluated as

     u  =  z + k

=>   u  =  -28 + 1.8

=>  u  =  -26.2 \ cm

The image distance is evaluated from lens formula as

       \frac{1}{v} = \frac{1}{f} + \frac{1}{u}

=>   \frac{1}{v} = \frac{1}{66.7} + \frac{1}{-26.2}

=>   v=- \frac{1}{0.0232}

=>    v=- 43 \ cm

The  near point is evaluated as

      n = -v +  k

=>    n =-(-43) +  1.8

=>    n =44.8 \ cm

3 0
3 years ago
How are atomic emission spectra like fingerprints for the elements
storchak [24]

Atomic emission spectra are like fingerprints for the elements, because it can show the number of orbits in that elements as well as the energy levels of that element. As each emission of atomic spectra is unique, it is the fingerprint of element.

<u>Explanation: </u>

Each element has unique arrangement of electrons in different energy levels or orbits. So depending upon the difference in energy of the orbital, the emission spectra will be varying for each element. As the binding energy and excitation energy is not common for any two elements, so the spectra obtained when those excited electrons will release energy to ground state will also be unique.

As in atomic emission spectra, the incident light will be absorbed by the electrons of those elements making the electron to excite, then the excited electron will return to ground state on emission of radiation of energy. Thus, this energy of emission is equal to the difference between the energy of initial and final orbital. So the spectra will act like fingerprints for elements.

8 0
3 years ago
A magnetic field of 37.2 t has been achieved at the mit francis bitter national magnetic laboratory. Find the current needed to
jeka57 [31]

Answer:

Here is the complete question:

https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632

a) Current for long straight wire  =3.7\ MA

b) Current at the center of the circular coil =2.48\times 10^{5}\ A

c) Current near the center of a solenoid 236.8\ A

Explanation:

⇒ Magnetic Field due to long straight wire is given by (B),where B=\frac{\mu\times I}{2\pi(r) },so\ I=\frac{B\ 2\pi(r)}{\mu}

\mu=4\pi \times 10^{-7}\ \frac{henry}{m}

Plugging the values,

Conversion 1\times 10^6 A = 1\ MA,and 2cm=\frac{2}{100}=0.02\ m

I=\frac{37.2\times \ 2\pi(0.02)}{4\ \pi \times (10^{-7})}=3.7\ MA

⇒Magnetic Field at the center due to circular coil (at center) is given by,B=\frac{\mu\times I (N)}{2(a)}

So I= \frac{2B(a)}{\mu\ N} = \frac{2\times 37.2\times 0.42}{4\pi\times 10^{-7}\times 100}=2.48\time 10{^5}\ A

⇒Magnetic field due to the long solenoid,B=\mu\ nI=\mu (\frac{N}{l})I

Then I=\frac{B}{\mu(\frac{N}{L})} \approx 236.8\A  

So the value of current are  3.7 MA,2.48\times 10^{5} A and 236.8\ A respectively.

8 0
3 years ago
How long does a 50 kW pump motor have to run to pump 500 cubic meters of water from a 180m deep mine
Ghella [55]

Answer:

t = 17658 s = 294.3 min = 4.9 h

Explanation:

The general formula for power is:

P = \frac{W}{t}

where,

P = Power of the Motor = 50 KW = 50000 W

W = Work Done by Motor = Change in P.E of Water = mgh

g = acceleration due to gravity = 9.81 m/s²

m = mass of  water = ρV

h = depth of water = 180 m

ρ = density of water = 1000 kg/m³

V = Volume of Water = 500 m³

t = time taken = ?

Therefore,

P = \frac{mgh}{t}=\frac{\rho Vgh}{t}\\\\t = \frac{\rho Vgh}{P}\\\\t = \frac{(1000\ kg/m^3)(500\ m^3)(9.81\ m/s^2)(180\ m)}{50000\ W}\\\\

<u>t = 17658 s = 294.3 min = 4.9 h</u>

6 0
3 years ago
If a running system has a total change in heat of 295 joules, and it's running at a temperature of 402 kelvin, what is the entro
Triss [41]
\[S = \Delta Q / T\] where S - entropy, Q heat and T temperature \[S = 295/402 = 0.733 \]
SO IT'S B 
8 0
3 years ago
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