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lisabon 2012 [21]
3 years ago
14

How are atomic emission spectra like fingerprints for the elements

Physics
1 answer:
storchak [24]3 years ago
8 0

Atomic emission spectra are like fingerprints for the elements, because it can show the number of orbits in that elements as well as the energy levels of that element. As each emission of atomic spectra is unique, it is the fingerprint of element.

<u>Explanation: </u>

Each element has unique arrangement of electrons in different energy levels or orbits. So depending upon the difference in energy of the orbital, the emission spectra will be varying for each element. As the binding energy and excitation energy is not common for any two elements, so the spectra obtained when those excited electrons will release energy to ground state will also be unique.

As in atomic emission spectra, the incident light will be absorbed by the electrons of those elements making the electron to excite, then the excited electron will return to ground state on emission of radiation of energy. Thus, this energy of emission is equal to the difference between the energy of initial and final orbital. So the spectra will act like fingerprints for elements.

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The body is subjected to a force of 0,4 N m with a shoulder of 5 cm. What is the magnitude of this force?​
igor_vitrenko [27]

Answer:

8N

Explanation:

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3 years ago
Calculate the size of the image of a tree that is 8m high and 80 m a pinhole camera that is 20 cm long . what is its magnificati
Vladimir79 [104]

1) Size of the image: 2 cm

In order to calculate the size of the image, we can use the following proportion:

p:q = h_o : h_i

where

p = 80 m is the distance of the tree from the pinhole

q = 20 cm = 0.2 m is the distance of the image from the pinhole

h_o = 8 m is the heigth of the object

h_i is the height of the image

By re-arranging the proportion, we find

h_i = \frac{h_o \cdot q}{p}=\frac{(8 m)(0.2 m)}{80 m}=0.02 m=2 cm


2) Magnification: 0.0025

The magnification of a camera is given by the ratio between the size of the image and the size of the real object:

M=\frac{h_i}{h_o}

so, in this problem we have

M=\frac{0.02 m}{8 m}=0.0025


4 0
3 years ago
About how many days in the moon’s cycle is it waxing?.
Monica [59]

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The volume of a cylindrical tin can with a top and a bottom is to be 16π cubic inches. If a minimum amount of tin is to be used
sergiy2304 [10]

Answer:

h = 4 in

Explanation:

GIVEN DATA:

volume of tin= 16 \pi

we know that

volume of cylinder is v = \pi r^2  h

so,

16 \pi = \pi r^2 h

16 = r^2 h

r = \sqrt{\frac{16}{h}}

construct formula for surface area

S = 2\pi r^2 +  2\pi rh

S = \frac{2v}{h} + 2 \sqrt{v \pi h}

minimize the function wrt  h

S' = \frac{2v}{h^2} + \sqrt{\frac{v \pi}{h} =  0

solving for h we have

h = [\frac{4 v}{\pi}]^{1/3}

we kow v = 16 \pi   so

h = 4 in

8 0
3 years ago
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photoshop1234 [79]

Answer:

The horse father from the center has a greater tangential speed. Although both horses complete one circle in the same time period, the one farther from the center covers a greater distance during that same period.

Explanation:

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