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insens350 [35]
3 years ago
11

If a running system has a total change in heat of 295 joules, and it's running at a temperature of 402 kelvin, what is the entro

py?
a.0.981 joules/kelvin

b.0.733 joules/kelvin

c.0.618 joules/kelvin

d.0.681 joules/kelvin
Physics
1 answer:
Triss [41]3 years ago
8 0
\[S = \Delta Q / T\] where S - entropy, Q heat and T temperature \[S = 295/402 = 0.733 \]
SO IT'S B 
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Answer:

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Explanation:

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we pick the positive one, so it takes 0.317s for the ball to hit on point A.

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x_{A}=V_{Ax}t

x_{A}=(20.38m/s)(0.317s)

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we pick the positive one, so it takes 0.468s for the ball to hit on point B.

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x_{B}=(20.88m/s)(0.468s)

x_{B}=9.77m

So once we got the two distances we can now find the difference between them:

x_{B}-x_{A}=9.77m-6.46m=3.31m

so the ball would have landed 3.31m farther if the downward angle were 6.0° instead.

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Answer:

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