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insens350 [35]
3 years ago
11

If a running system has a total change in heat of 295 joules, and it's running at a temperature of 402 kelvin, what is the entro

py?
a.0.981 joules/kelvin

b.0.733 joules/kelvin

c.0.618 joules/kelvin

d.0.681 joules/kelvin
Physics
1 answer:
Triss [41]3 years ago
8 0
\[S = \Delta Q / T\] where S - entropy, Q heat and T temperature \[S = 295/402 = 0.733 \]
SO IT'S B 
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Two antennas located at points A and B are broadcasting radio waves of frequency 96.0 MHz, perfectly in phase with each other. T
earnstyle [38]

Answer:

a)   Δφ = 1.51 rad , b)  x = 21.17 m

Explanation:

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          Δr /λ = Δfi / 2π

          Δfi = Δr /λ 2π

          Δr = r₂-r₁

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We use Pythagoras' theorem for the other distance

         r₂ = √ (x² + y²)

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        c =  λ f

          λ = c / f

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b) for destructive interference the path difference must be λ/2, the equation for destructive interference with φ = π remains

           Δr = (2n + 1) λ / 2

           

For the first interference n = 0

           Δr = λ / 2

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          x² + y² = (1.56 + x)²

          x² + y² = 1.56² + 2 1.56 x + x²

          y2 = 20.4336 +3.12 x

          x = (y² -20.4336) /3.12

          x = (9.3² -20.4336) /3.12

          x = 21.17 m

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