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pashok25 [27]
3 years ago
10

Dana is on a train traveling at a speed of 20 km/h. Dana walks from the front of the train to the back of the train at a speed o

f 4 km/h. What is Dana’s speed relative to the ground?
a.) 20 km/h
b.) 12 km/h
c.) 16 km/h
d.) 24 km/h
Physics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

Answer:

Option C

16 Km/h

Explanation:

Dana is moving in opposite direction compared to the train.If we denote w-velocity of train with respect to ground and u- velocity of passenger with respect to train and v-velocity of passenger we can using classical mechanics claim that v = w-u

v=20-4=16 km/h

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A negative charge of -0.550 m exerts an upward <a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="5868766e
almond37 [142]

Answer:

a. +10.9μC

b. 0.600N and downward

Explanation:

To determine the magnitude of the charge, we use the force rule that exist between two charges which us expressed as

F=(kq₁q₂)/r²

since q₁=-0.55μC and the force it applied on the charge above it is upward,we can conclude that the second charge is +ve, hence we calculate its magnitude as

q₂=Fr²/kq₁

q₂=(0.6N*0.3²)/(9*10⁹*0.55*10⁻⁶)

q₂=0.054/4950

q₂=1.09*10⁻⁵c

q₂=10.9μC.

Hence the second charge is +10.9μC

b. From the rule of charges which state that like charges repel and unlike charges attract, we can conclude that the two above charges will attract since they are unlike charges. Hence the direction of the force will be downward into the second charge and the magnitude of the force will remain the same as 0.600N

8 0
3 years ago
If you triple the speed from 20km/h to 60km/h, by what factor does the KE increase?
sertanlavr [38]

Answer:

<em>The kinetic energy increases by a factor of 9 </em>

Explanation:

<u>Kinetic Energy </u>

It's the energy related to the speed of an object and is calculated by the formula

\displaystyle K=\frac{mv^2}{2}

Let's suppose the initial speed of the mass is v_o, then the kinetic energy is

\displaystyle K_o=\frac{mv_o^2}{2}

Now the speed will triple, i.e. v_1=3v_o. The new kinetic energy is

\displaystyle K_1=\frac{mv_1^2}{2}

\displaystyle K_1=\frac{m(3v_o)^2}{2}

\displaystyle K_1=9\frac{mv_o^2}{2}

Thus

K_1=9K_o

The kinetic energy increases by a factor of 9

Let's check with numbers: v_o=20,\ v_1=60

\displaystyle K_o=\frac{m20^2}{2}=200m

\displaystyle K_1=\frac{m60^2}{2}=1800m

The relation is

\displaystyle \frac{K_1}{K_o}=9

The new kinetic energy is nine times the initial kinetic energy.

5 0
3 years ago
Please help I’m almost done with exam
Zielflug [23.3K]

Answer:

D

Explanation:

Telescopes detect electromagnetic waves from space and it travels back to the telescope lens in order for you to see.

7 0
3 years ago
Read 2 more answers
Calculate the force on an object that has a mass of 12 kg and an acceleration of 4 m/s^2
kati45 [8]
Remember Newton's Second Law F = mass * acceleration

mass = 12 kg
acceleration = 4 m/s^2

F = 12 * 4 = 48 N
8 0
3 years ago
The average density of the body of a fish is 1080kg/m^3 . To keep from sinking, the fish increases its volume by inflating an in
MArishka [77]

Answer:

Increase of volume (F)  = 8.01%

Explanation:

Given:

Density of fish = 1,080 kg/m³

Density of water = 1,000 kg/m³

density of air = 1.28 kg/m³

Find:

Increase of volume (F)

Computation:

1,080 kg/m³  + [F × 1.28 kg/m³ ] = (1+F) × 1,000 kg/m³  

1,080 + 1.28 F =1,000 F + 1,000

80 = 998.72 F

F = 0.0801 (Approx)

F = 8.01%  (Approx)

7 0
3 years ago
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