the sum of the angles in a triangle = 180°, thus
x + 
x + 
x = 180
multiply through by 6
6x + 3x + x = 1080
10x = 1080 ( divide both sides by 10 )
x = 108
the angles are 108°, 54° and 18°
Since all the angles are different and the largest is 108°
The triangle is an obtuse scalene triangle
Now, the cosecant of θ is -6, or namely -6/1.
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now
recall that
therefore, let's just plug that on the remaining ones,
now, let's rationalize the denominator on tangent and secant,
Im confused. Its not equal to any of the choices
Unless C is the cube root of 32^5.
[t3] \sqrt[n]{x} [32^5]
