Answer:
The current flows through the rod is 14.9 A.
Explanation:
Given that,
Magnetic field = 0.045 T
Mass of aluminum rod = 0.19 kg
Length = 1.6 m
Angle = 30.0°
We need to calculate the force
Using resolving force
Put the value into the formula
We need to calculate the current flows through the rod
Using formula of magnetic force
Put the value into the formula
Hence, The current flows through the rod is 14.9 A.
Half-life<span> is defined as the time it takes for one-</span>half<span> of the atoms of a radioactive material to disintegrate. </span>Half-lives<span> for various </span>radioisotopes<span> can range from a few microseconds to billions of years.</span>
For the project draw a labeled diagram of water reservoir, that is hydroelectric power station, where water comes through different water sources like precipitation, and through rivers get collected in dams( water reservoirs), from here water falls on turbines and rotate them, by rotation of turbine energy is produced, and than finally this energy through transformers gets converted into electricity.
In this example you have all types of energy that is required to complete your project.
For example when water is running in rivers , it has kinetic energy, when gets collected in dam( reservoir) ,it has potential energy, when falls on turbines it gets converted into mechanical energy, and finally through transformers gets transformed into electricity, that is electric energy.
so it's all about the law of energy conservation.
Answer:
-20.0 m/s and 30.0 m/s
Explanation:
Momentum is conserved:
m (30.0) + m (-20.0) = m v₁ + m v₂
30.0 − 20.0 = v₁ + v₂
10.0 = v₁ + v₂
Since the collision is perfectly elastic, energy is also conserved. Since there's no rotational energy or work done by friction, the initial kinetic energy equals the final kinetic energy.
½ m (30.0)² + ½ m (-20.0)² = ½ mv₁² + ½ mv₂²
(30.0)² + (-20.0)² = v₁² + v₂²
1300 = v₁² + v₂²
We now have two equations and two variables. Solve the system of equations using substitution:
1300 = v₁² + (10 − v₁)²
1300 = v₁² + 100 − 20v₁ + v₁²
0 = 2v₁² − 20v₁ − 1200
0 = v₁² − 10v₁ − 600
0 = (v₁ + 20) (v₁ − 30)
v₁ = -20, 30
If v₁ = -20, v₂ = 30.
If v₁ = 30, v₂ = -20.
So either way, the final velocities are -20.0 m/s and 30.0 m/s.
