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slamgirl [31]
3 years ago
6

Suppose that you find in a reference book that the volume of all the oceans is 1.4×109km3. To find the mass, you can use the den

sity of water, also found in this reference book, but first you must convert the volume to cubic meters. What is this volume in cubic meters?
Physics
1 answer:
lesya [120]3 years ago
5 0
1(km)cubed = (1,000 m) x (1,000 m) x (1,000 m) = 1 billion cubic meters

1.4 x 10 to the 9 cubic km = 1.4 x 10 to the 9 x (10 to the 9 cubic meters) =

1.4 x 10 to the 18 cubic meters.
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What kind of EM waves are most dangerous to humans​
zhuklara [117]

The most dangerous frequencies of electromagnetic energy are X-rays, gamma rays, ultraviolet light and microwaves. X-rays, gamma rays and UV light can damage living tissues, and microwaves can cook them. Hope this helps! =^-^=

4 0
3 years ago
a 1500 kg car traveling at 15 m/s to the south collides with a 4500 kg truck that is intially at rest at a spotlight. The car an
harkovskaia [24]

Answer:

3.75 m/s south

Explanation:

Momentum before collision = momentum after collision

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

Since the car and truck stick together, v₁ = v₂.

m₁ u₁ + m₂ u₂ = (m₁ + m₂) v

Given m₁ = 1500 kg, u₁ = -15 m/s, m₂ = 4500 kg, and u₂ = 0 m/s:

(1500 kg) (-15 m/s) + (4500 kg) (0 m/s) = (1500 kg + 4500 kg) v

-22500 kg m/s = 6000 kg v

v = -3.75 m/s

The final velocity is 3.75 m/s to the south.

4 0
3 years ago
Read 2 more answers
Two large non-conducting plates of surface area A = 0.25 m 2 carry equal but opposite charges What is the energy density of the
Stells [14]

Answer:

5.1*10^3 J/m^3

Explanation:

Using E = q/A*eo

And

q =75*10^-6 C

A = 0.25

eo = 8.85*10^-12

Energy density = 1/2*eo*(E^2) = 1/2*eo*(q/A*eo)^2 = [q^2] / [2*(A^2)*eo]

= [(75*10^-6)^2] / [2*(0.25)^2*8.85*10^-12]

= 5.1*10^3 J/m^3

8 0
3 years ago
A 6 m/s vector pointing North is added to a 2 m/s vector pointing East. What are the magnitude and direction of the resultant?
irina [24]

Answer:

A + B = C      Ax = 2   Ay = 0    Bx = 0  By = 6

Ax + Bx = Cx = 2

Ay + By = Cy = 6

C = (2^2 + 6^2)^1/2 = 6.32

Tan Cy / Cx = 6 / 2 = 3

Cy at 71.6 deg

6 0
3 years ago
An angle marking is like a meter stick marking. The marking of 1.2m on a meter stick only means an object is 1.2m long if the ob
grandymaker [24]

Answer:

The angle of bend = 20°

Explanation:

Since the question describes that the angle marking is similar to the metre stick marking.

The length of the object when it begins at 0 meters on the meter rule

= 1.2 m

The length of the meter stick when it begins at 0.2 m on the meter rule

= 1.0 m

The difference in length of the object based on the markings

= 1.2 - 1.0 = 0.2 m

If the green marking is on 223°, i.e. θ₂ = 223°

and the straight marking is on 253°, i.e.  θ₁ = 253°

The angle of bend =  θ₁ -  θ₂

The angle of bend = 253° - 223°

The angle of bend = 20°

6 0
3 years ago
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