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uysha [10]
3 years ago
12

An object is measured 6.0cm in length, 3.0cm in width and 5.0cm in height. What is it’s volume?

Physics
1 answer:
sergey [27]3 years ago
5 0

Answer:

90

Explanation:

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Volume can be measured in: <br>A. cubic centimeters. <br>B. centimeters. <br>C. square centimeters.
Ad libitum [116K]

Answer-

A. cubic centimeters.

Hope this helps!

8 0
3 years ago
Read 2 more answers
How much work is done in holding a 20 N sack of potatoes while waiting in line at the
Yuki888 [10]

Answer: A

Explanation:

honestly, it sounded the best

8 0
2 years ago
A blank is any disturbance that carries energy from one place to another through matter and space.
Eduardwww [97]
<h3>Answer;</h3>

<em>A wave </em>

<em><u>A wave</u></em> is any form of a disturbance that carries energy from one place to another through a matter and space

<h3>Explanation;</h3>
  • Waves carry energy from one point, the source to another point or place. The transmission of a wave may occur through the space or through a material medium.
  • Electromagnetic waves are those waves whose transmissions occurs through the space, they do not require material medium for transmission,for example, radio waves, while mechanical waves are those that require material medium for transmission, for example sound waves.
  • The energy of wave depends on the frequency of the wave and the wavelength of that particular wave.
8 0
3 years ago
Read 2 more answers
Which is one-dimensional
Tema [17]

Answer:

B

Explanation:

They are all one-dimensional

6 0
3 years ago
If an object force of 50 N is used to move an object a distance of 20 m, what distance must the object be moved if the input for
steposvetlana [31]

Answer:

\ d_{out} = 100 \ m.

Explanation:

Given data:

F_{in} = 50 \ \rm N

F_{out} = 10 \ \rm N

d_{in} = 20 \ m

Let the distance traveled by the object in the second case be d_{out}.

In the given problem, work done by the forces are same in both the cases.

Thus,

W_{in} = W_{out}

F_{in}.d_{in} = F_{out}.d_{out}

\Rightarrow \ d_{out} = \frac{F_{in}.d_{in}}{F_{out}}

\ d_{out} = \frac{50 \times 20}{10}

\ d_{out} = 100 \ m.

5 0
3 years ago
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