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2 years ago

An object is measured 6.0cm in length, 3.0cm in width and 5.0cm in height. What is it’s volume?

Physics

1 answer:

sergey [27]2 years ago

5 0

Answer:

Explanation:

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A phoneme is the largest unit of sound in a word. TRUE or FALSE.

Degger [83]

The answer to the question is False i.e A phoneme is not the largest unit of sound.

EXPLANATION:

Phoneme is related to linguistics or the sound system of language which is the language specific.

It is defined as the smallest contrastive unit of sound in speech which can give a distinct meaning. It distinguishes one word from the other word in a unique way .When we put all the phonemes of a particular word, the corresponding word is formed .

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2 years ago

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What is the gain in gravitational potential energy of a body of weight 2000N as it rises from a height of 20m to a height of 25

monitta

Answer:

Explanation:

GPE =weight * height

= 2000*(25-20)

= 10000 J

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2 years ago

Ahmed kept a balloon from his birthday for several days until it began to deflate and slowly sink to the ground. He wondered how

goldfiish [28.3K]

<span>He should study the chapter about laws to get a better understanding about the laws that govern physical objects</span>

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2 years ago

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The lightbulb is an example of

AlexFokin [52]

A object that has been reinvented so it is more energy efficient

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3 years ago

A kangaroo can jump over an object 2.46 m high. (a) Calculate its vertical speed (in m/s) when it leaves the ground.

Elenna [48]

Answer:

a) 6.95 m/s

b) 1.42 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow -u^2=2\times -9.81\times 2.46-0^2\\\Rightarrow u=\sqrt{2\times 9.81\times 2.46}\\\Rightarrow u=6.95\ m/s$

a) The vertical speed when it leaves the ground. is 6.95 m/s

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-6.95}{-9.81}\\\Rightarrow t=0.71\ s$

Time taken to reach the maximum height is 0.71 seconds

$s=ut+\frac{1}{2}at^2\\\Rightarrow 2.46=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{2.46\times 2}{9.81}}\\\Rightarrow t=0.71\ s$

Time taken to reach the ground from the maximum height is 0.71 seconds

b) Time it stayed in the air is 0.71+0.71 = 1.42 seconds

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3 years ago