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kramer
3 years ago
7

A spring stretches by 0.0208 m when a 3.39-kg object is suspended from its end. How much mass should be attached to this spring

so that its frequency of vibration is f?
Physics
1 answer:
sashaice [31]3 years ago
4 0

Answer:

COMPLETE QUESTION

A spring stretches by 0.018 m when a 2.8-kg object is suspended from its end. How much mass should be attached to this spring so that its frequency of vibration is f = 3.0 Hz?

Explanation:

Given that,

Extension of spring

x = 0.0208m

Mass attached m = 3.39kg

Additional mass to have a frequency f

Let the additional mass be m

Using Hooke's law

F= kx

Where F = W = mg = 3.39 ×9.81

F = 33.26N

Then,

F = kx

k = F/x

k = 33.26/0.0208

k = 1598.84 N/m

The frequency is given as

f = ½π√k/m

Make m subject of formula

f² = ¼π² •(k/m

4π²f² = k/m

Then, m4π²f² = k

So, m = k/(4π²f²)

So, this is the general formula,

Then let use the frequency above

f = 3Hz

m = 1598.84/(4×π²×3²)

m = 4.5 kg

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<h3>What is called Wavelength?</h3>

The wavelength can be defined as the separation between wave crests. Additionally, a wide variety of objects move in waves, including light, the earth or ground, water, strings, air, and sound waves. Furthermore, we use the Greek letter lambda to denote the wave's wavelength. In addition, the wave's wavelength is determined by dividing its velocity by its frequency. Additionally, we employ meters (m), which is the unit used to indicate wavelength in meters.

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