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goldfiish [28.3K]
4 years ago
5

The image illustrates that as the distance between two objects increases, the force of gravity ____________. A) decreases. B) in

creases. C) remains the same. D) increases then decreases.
Physics
2 answers:
emmainna [20.7K]4 years ago
7 0
The image is missing (however it's not necessary to solve the problem).

The correct answer is A) decreases, because the gravitational force is inversely proportional to the square of the distance. In fact, the magnitude of the gravitational force between two object of mass M and m, at a distance d one from each other, is
F=G \frac{Mm}{d^2}
where G is the gravitational constant. As can be seen from the formula, if the distance d between the two object increases, the intensity of the force decreases.
Tema [17]4 years ago
3 0

B; Decreases

Because,

The image illustrates that as the distance between two objects increases, the force of gravity decrease. The strength of gravity is affected by the distance between two objects as well as their masses

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Answer:

Energy expenditure in K cals/min = 10 K cals /min (approximately)

Explanation:

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Energy expenditure in Kcal/min=  METs x 3.5 x Body weight (kg) / 200

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putting the values in formula,

Energy expenditure in K cals/min=  7.6 x 3.5 x 78.02 / 200

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3 years ago
A 25-kg wagon has a momentum of 300kg m/s. What is it’s acceleration?
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Which energy transfer occurs when a cube of ice is placed in a glass of<br> water?
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The indicated data are of clear understanding for the development of Airy's theory. In optics this phenomenon is described as an optical phenomenon in which The Light, due to its undulatory nature, tends to diffract when it passes through a circular opening.

The formula used for the radius of the Airy disk is given by,

y_r=1.22\frac{\lambda f}{d}

Where,

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Our values are given by,

State 1:

d=2.00mm = 2*10^{-3}m

f= 25mm = 25*10^{-3}m

\lambda = 750nm = 750*10^{-9}m

State 2:

d=8.00mm = 8*10^{-3}m

f= 25mm = 25*10^{-3}m

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Replacing in the first equation we have:

y_{r1} = 1.22\frac{(750*10^{-9})(25*10^{-3})}{2*10^{-3}}

y_{r1}= 11.4\mu m

And also for,

y_{r2} =1.22\frac{(390*10^{-9})(25*10^{-3})}{8*10^{-3}}

y_{r2} = 1.49\mu m

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i got it from goo.gle but i hope that helps:)

have a good day bro

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