Answer:
B) the full spectrum of light
Explanation:
It is reacting as a chemical reaction .
Molar solubility of AgCl will be 0.59 ×
M.
The amount of a chemical that can dissolve in one liter of a solution before reaching saturation is known as its molar solubility. This implies that the quantity of a substance it can disintegrate in a solution even before the solution becomes saturated with that particular substance is determined by its molar solubility.
A compound's molar solubility would be the measure of how many moles of such a compound must dissolve to produce one liter of saturated solution. The molar solubility unit will be mol L-1.
Calculation of molar solubility:
Given data:
M = 0.30 M
= 1.77 × 
The reaction can be written as:
AgCl ⇔ 
s s (s+0.30)
= [
]+ [
]
1.77 ×
= s (0.30)
s = 1.77 ×
/ 0.3
s = 0.59 ×
M
Therefore, molar solubility of AgCl will be 0.59 ×
M.
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The moles which were measured out is calculated using the following formula
moles = mass/molar mass
molar mass of CuBr2.4H20 = 63.5 Cu + ( 2 x79.9) br + ( 18 x4_) h20 = 295.3 g/mol
moles is therefore= 5.2 g/ 295.3 g/mol= 0.0176 moles