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2 years ago

Explain why a nanowire can be longer than 3000nm but still be considered a metallic nanomaterial

Chemistry

1 answer:

Ksivusya [100]2 years ago

8 0

Answer:

A nanowire is a nanostructure, with the diameter of the order of a nanometre (10−9 meters). It can also be defined as the ratio of the length to width being greater than 1000. Alternatively, nanowires can be defined as structures that have a thickness or diameter constrained to tens of nanometers or less and an unconstrained length. At these scales, quantum mechanical effects are important—which coined the term "quantum wires". Many different types of nanowires exist, including superconducting (e.g. YBCO[1]), metallic (e.g. Ni, Pt, Au, Ag), semiconducting (e.g. silicon nanowires (SiNWs), InP, GaN) and insulating (e.g. SiO2, TiO2). Molecular nanowires are composed of repeating molecular units either organic (e.g. DNA) or inorganic (e.g. Mo6S9−xIx).

Explanation:

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2 years ago

A ____________ alkene is more stable than a ____________ alkene because they have fewer steric interactions. In an elimination r

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Answer:

See explanation

Explanation:

A trans alkene is more stable than a cis alkene because they have fewer steric interactions.

⇒ In a cis alkene there is steric hindrance, because the methyl groups are on the same side of the double bond.

Because of this steric crowding, there are van der Waals repulsive forces between the electron clouds of the groups.

This decreases the stability of the cis alkene.

In an elimination reaction, a geometry where the β hydrogen and the leaving group are on opposite sides of the molecule is called anti periplanar.

⇒ 'Anti’ refers to the two functional groups lying on opposite sides of the plane of the bond

In an SN1 mechanism, a nucleophile attacks the carbocation, forming a substitution product,

⇒ The SN1 reaction is a substitution reaction, and means "nucleophilic substitution".The "1" says that the rate-determining step is unimolecular. Thus, the rate equation is often shown as having first-order dependence on electrophile and zero-order dependence on nucleophile.

while in an E1 mechanism, a base removes a β hydrogen from the carbocation, forming a new π-bond.

⇒ E1 indicates a elimination, unimolecular reaction

This implies that the rate determining step of the mechanism depends on the decomposition of a single molecular species.

.This is a classic elimination reaction – forming a new C–C(π) bond, and breaking a C–H and C–leaving group bond.

CH3CH2Br and NaOH react by an SN2 mechanism.

⇒ It's a type of reaction mechanism that is common in organic chemistry, where one bond is broken and one bond is formed, synchronously, (in one step.)

Stronger bases, like hydroxide, favor E2 reactions, whereas weaker bases, like water favor, E1 reactions

Disubstituted alkenes always have the possibility to exist as two different Diastereomer.

Diastereomer are stereoisomers that are not mirror images of one another and are non-superimposable on one another. They exist (always) in 2 forms.

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2 years ago

Calculate the theoretical carbonaceous and nitrogenous oxygen demand for:

serg [7]

Answer:

The correct answer is 129 mg and 232 mg.

Explanation:

Theoretical carbonaceous oxygen demand:

The reaction will be,

C₂H₆O₂ + 5/2 O₂ ⇒ 2CO₂ + 3H₂O

Thus, for one mole of C₂H₆O₂ (ethylene glycol), 2.5 moles of O₂ is needed.

The molecular mass of ethylene glycol is 62 grams per mole.

The given mass of ethylene glycol is 100 mg or 0.1 grams

The moles of ethylene glycol will be,

Moles = Weight/Molecular mass

= 0.1/62 = 1.613 × 10⁻³ mol

For 1.613 × 10⁻³ mol, the moles of O₂ will be,

= 2.5×1.613×10⁻³

= 4.0.×10⁻³ × 32mol

= 0.129 grams or 129 mg.

The theoretical nitrogenous oxygen demand is:

The reaction will be,

2NH₃-N + 9/2O₂ ⇒ 4HNO2 + H₂O

Thus, for 2 moles of NH₃-N, 4.5 moles of O₂ is needed,

Therefore, for 1 mol of NH₃-N, the oxygen required will be,

= 4.5/2 = 2.25 mol

The given mass of NH₃-N is 100 mg, the moles of NH₃-N will be,

Moles = 100×10⁻³/31 = 3.225 × 10⁻³ mol (The molecular mass of NH₃-N is 31 gram per mole)

The moles of O₂ is 2.25 × 3.225 × 10⁻³ = 7.258 × 10⁻³ mol.

Now the mass of O2 will be,

= 7.258 × 10⁻³ × 32

= 0.232 grams

= 232 mg

5 0

3 years ago

Explain why a nanowire can be longer than 3000nm but still be considered a metallic nanomaterial​

Explain why a nanowire can be longer than 3000nm but still be considered a metallic nanomaterial