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sergejj [24]
3 years ago
14

Problem 3.100 a chemical plant uses electrical energy to decompose aqueous solutions of nacl to give cl2,h2, and naoh: 2nacl(aq)

+2h2o(l)→2naoh(aq)+h2(g)+cl2(g) part a if the plant produces 1.5×106 kg (1500 metric tons) of cl2 daily, estimate the quantities of h2 produced.
Chemistry
1 answer:
chubhunter [2.5K]3 years ago
4 0

First we calculate the number of moles of Cl2, that is:

moles Cl2 = 1.5*10^10 grams/71 grams/mol = 211267605.633802817 mol = 2.1 * 10 ^ 8 mole = x <span>

So that based on stoichiometry, the number of moles of NaOH = 2x and that of H2 = x mol 

mass of NaOH = 4.2*10^8 * 40 =168*10^8 grams = 1.68 * 10^6 kg = 1.68 metric tons 

<span>mass of H2 = 2.1*10^8 * 2 = 4.2*10^8 grams = 0.042 * 10^6 kg = 0.042 metric tons.</span></span>

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How many molecules are in 20.0 L(liters) of SO2 at STP
Finger [1]

5.4 x 10²³ molecules

Explanation:

Given parameter

Volume of gas = 20L

Condition of reaction = STP

Unknown:

number of molecules

Solution:

The number of molecules of a substance is given by;

   Number of molecules = Number of moles x avogadro's constant

Number of moles at stp = \frac{volume of gas}{22.4}

 Number of moles of SO₂ = \frac{20}{22.4} = 0.893mole

Number of molecules = 0.893 x 6.02 x 10²³ = 5.4 x 10²³ molecules

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Number of molecules brainly.com/question/10818009

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4 0
3 years ago
Use the ΔHrxn values of the following reactions: 2SO2(g) + O2(g) → 2SO3(g) ΔHrxn = –196 kJ 2S(s) + 3O2(g) → 2SO3(g) ΔHrxn = –790
sesenic [268]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -297 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

S(s)+O_2(g)\rightarrow SO_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)    \Delta H_1=-196kJ

(2) 2S(g)+3O_2(g)\rightarrow 2SO_3(g)     \Delta H_2=-790kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=\frac{[1\times (-\Delta H_1)]+[1\times \Delta H_2]}{2}

Putting values in above equation, we get:

\Delta H^o_{rxn}=\frac{[(1\times -(-196))+(1\times (-790))}{2}=-297kJ

Hence, the \Delta H^o_{rxn} for the reaction is -297 kJ.

8 0
3 years ago
How many moles of Br atoms are in .5 mol of Br2 molecules
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Br2 5mol take a 10 mol Br atoms mol
5 0
3 years ago
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Name the element described in each of the following:
borishaifa [10]

Alkaline earth metal whose cation isoelectric with Kr is strontium (Sr).

What is Alkaline earth metal?

Six chemical elements from group 2 of the periodic chart make up the alkaline earth metals. They are boron (R), barium (Ba), calcium (Ca), strontium (Sr), magnesium (Mg), beryllium (Be), and radium (Ra). The elements share many characteristics, including being glossy, silvery-white, moderately reactive metals at standard pressure and temperature.

They share a full outer s-orbital structurally, meaning that this orbital includes all two of its electrons, which the alkaline earth metals rapidly lose to form cations with a charge of +2 and an oxidation state of +2.

All of the identified alkaline earth metals are found in nature, albeit radium is not a primordial element but only appears as part of the decay chain of uranium and thorium.

The chemical element strontium has the atomic number 38 and the symbol Sr. Strontium is a soft, silver-white, yellowish metallic element that is an alkaline earth metal and has a strong reactivity to chemicals. When the metal is exposed to air, a thick layer of dark oxide forms. Similar to its two vertical neighbors in the periodic table, barium and calcium, strontium exhibits physical and chemical characteristics. It is mostly obtained from the minerals celestine and strontianite, where it is found naturally.

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8 0
2 years ago
A 100.0 mL solution containing 0.864 g of maleic acid (MW=116.072 g/mol) is titrated with 0.276 M KOH. Calculate the pH of the s
Lilit [14]

Answer:

pH = 1.32

Explanation:

                 H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺

This problem involves a weak diprotic acid which we can solve by realizing they amount  to buffer solutions.  In the first  deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:

So first calculate the moles reacted and produced:

n H₂M = 0.864 g/mol x 1 mol/ 116.072 g  =  0.074 mol H₂M

54 mL x  1L / 1000 mL x 0. 0.276 moles/L = 0.015 mol KOH

it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.

moles H₂M left = 0.074 - 0.015 = 0.059

moles HM⁻ produced = 0.015

Using the Henderson - Hasselbach equation to solve for pH:

ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325

Notes: In the HH equation we used the moles of the species since the volume is the same and they will cancel out in the quotient.

For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.

           

3 0
3 years ago
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