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3 years ago

What is the calculation for elastic potential?

1 answer:

3 0

Elastic potential energy is equal to the force times the distance of movement. Elastic potential energy = force x distance of displacement. Because the force is = spring constant x displacement, then the Elastic potential energy = spring constant x displacement squared.

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Tina is driving her sports car down US1, traveling 27m/s. She sees her friend Rita up ahead, waiting to cross the street at the

mrs_skeptik [129]

Answer:

434 Hz

Explanation:

According to the Doppler effect, when a source of a wave is moving towards an observer at rest, then the observer will observe an apparent frequency which is higher than the original frequency of the source.

In this situation, Tina is driving towards Rita. Tina is the source of the sound wave (the horn), while RIta is the observer. Since the original frequency of the sound is 400 Hz, Rita will hear a sound with a frequency higher than this value.

The only choice which is higher than 400 Hz is 434 Hz, so this is the frequency that Rita will hear.

3 0

3 years ago

A baseball has a mass of 0. 45 kg and is thrown with a speed of 25 m/s. What is the momentum of the baseball? 0. 018 kg â€˘ mete

aleksandr82 [10.1K]

Answer:

11 Kg.m/s

Explanation:

P=mv

P=0.45*25

P=11.25 Kg.m/s

3 0

2 years ago

A jetliner, traveling northward, is landing with a speed of 71.9 m/s. Once the jet touches down, it has 675 m of runway in which

Leviafan [203]

Answer:

The value is $a = -3.7 \ m/s^2$

Explanation:

From the question we are told that

The landing speed is $u = 71.9 \ m/s$

The distance traveled is $d = 675 \ m$

The velocity it is reduced to is $v = 11.3 \ m/s$

Generally the average acceleration is mathematically represented as

$a = \frac{ v^2 - u^2 }{ 2 * d }$

=> $a = \frac{ 11.3^2 - 71.9^2 }{ 2 * 675 }$

=> $a = -3.7 \ m/s^2$

5 0

3 years ago

A thin rod has a length of 0.288 m and rotates in a circle on a frictionless tabletop. The axis is perpendicular to the length o

kakasveta [241]

Answer:

0.152724283058 rad/s

Explanation:

$\omega_i=0.602\ rad/s$

In this system the angular momentum is conserved

$L_i=L_f\\\Rightarrow 1.22\times 10^{-3}\times 0.602=(1.22\times 10^{-3}+5\times 10^{-3}\times 0.288)\omega_f\\\Rightarrow \omega_f=\dfrac{1.22\times 10^{-3}\times 0.602}{(1.22\times 10^{-3}+5\times 10^{-3}\times 0.288^2)}\\\Rightarrow \omega_f=0.449275716942\ rad/s$

Change in angular velocity is

$\Delta \omega=0.449275716942-0.602=-0.152724283058\ rad/s$

The change in angular velocity is 0.152724283058 rad/s

5 0

3 years ago

The speed of sound in humid air than in dry air. Why

Elden [556K]

Answer:

When moisture is removed from air, its density increases. The speed of sound in a humid air is inversely proportional to the square root of its density. Therefore, the speed of sound in moist air is humidity increases, the velocity of sound increase and vice-versa.

Hope it helps :)

3 0

3 years ago