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yawa3891 [41]
3 years ago
11

The manufacturer of a 1.5 V D flashlight battery says that the battery will deliver 9 mA for 42 continuous hours. During that ti

me the voltage will drop from 1.5 V to 1.0 V. Assume the drop in voltage is linear with time.
How much energy does the battery deliver in this 37h interval?
Physics
1 answer:
Sladkaya [172]3 years ago
4 0

Answer:

The manufacturer of a 9V dry-cell flashlight battery says that the battery will deliver 20 mA for 80 continuous hours. During that time the voltage will drop from 9V to 6V. Assume the drop in voltage is linear with time. How much energy does the battery deliver in this 80 h interval?

Explanation:

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Two similar waves X and Y travel through the same medium. Wave X has a frequency of 200 hertz and a
velikii [3]

Answer:

The correct solution is option A "10 meters".

Explanation:

The given values are:

Wave X,

Frequency,

F_x=200 \ H_z

Wavelength

\lambda_x=35 \ m

Wave Y,

Frequency,

F_y=700 \ Hz

Let its wavelength = \lambda_y

As we know,

⇒  v=f \lambda

For both waves, medium is same then

⇒  v_x=v_y

⇒  f_x \lambda_x=f_y \lambda_y

then,

⇒  \lambda_y=\frac{f_x \lambda_x}{f_y}

On substituting the estimated values in the above equation, we get

⇒      =\frac{200\times 35}{700}

⇒      =\frac{7000}{700}

⇒      =10 \ m

4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Ivahew [28]
B trend line is right
5 0
3 years ago
Read 2 more answers
Consider a stone in free fall on a planet with gravitational acceleration 3.4 m/s^2. Suppose you would like the stone to experie
Stella [2.4K]

Answer:

Angle of incline is 20.2978°

Explanation:

Given that;

Gravitational acceleration on a planet a = 3.4 m/s²

Gravitational acceleration on Earth g = 9.8 m/s²

Angle of incline = ∅

Mass of the stone = m

Force on the stone along the incline will be;

F = mgSin∅

F = ma

The stone has the same acceleration as that of the gravitational acceleration on the planet.

so

ma = mgSin∅

a = gSin∅

Sin∅ = a / g

we substitute

Sin∅ = (3.4 m/s²) / (9.8 m/s²)

Sin∅ = 0.3469

∅ = Sin⁻¹( 0.3469 )

∅ = 20.2978°

Therefore, Angle of incline is 20.2978°

8 0
3 years ago
The length of the mercury thread is found to be 4cm and 24cm at ice point and steam point respectively on an ungraduated thermom
BabaBlast [244]

Answer:

The difference between ice and steam in Celsius (Centigrade) is 100 deg.

So the difference between and 4 cm and 24 cm of the thread corresponds to 100 deg C.

So 8 cm is 4 cm greater than the ice point

4 cm / 20 cm = 1/5     since the steam point and the ice point are 20 cm apart

Then 1/5 * 100  deg C = 20 deg C   the requested temperature

6 0
3 years ago
A battery charger is connected to a dead battery and delivers a current of 8.9 A for 4.7 hours, keeping the voltage across the b
adell [148]

Answer:

1807.56 kJ

Explanation:

Parameters given:

Current, I = 8.9A

Time, t = 4.7hrs = 4.7 * 3600 = 16920 secs

Voltage, V = 12V

Electrical energy is given as:

E = I*V*t

Where I = Current

V = Voltage/Potential differenxe

t = time in seconds.

E = 8.9 * 12 * 16920

E = 1807056 J = 1807.056 kJ

3 0
3 years ago
Read 2 more answers
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