Density = mass/volume
= 4300/10000
= 0.43 g/mL.
Therefore density of liquid propane is 0.43 g/mL.
Hope this helps!
It is the distance between one peak to the next in the wave. Calculated as wavelength(meters) = 300/frequency(MHz)
Answer:
So then we will have at least 75% of the data within two deviations from the mean .
So then the interval would be (97.14, 99.5)
Explanation:
Previous concepts
Chebyshev’s rule is appropriate for any distribution. "Chebyshev’s inequality applies to all distributions, regardless of shape". And is useful since provides a "minimum percentage of the observations that lies within k standard deviations of the mean. "
If k = 2, at least 3/4 of the measurements lie within 2 standard deviations to within the mean.
And the general formula is (1-1/k^2) represent the fraction of the data within the mean .
Solution to the problem
For this case we want to find the percentage of data that would be at least within two deviations from the mean so for this case the value of k =2 and if we replace we got:
So then we will have at least 75% of the data within two deviations from the mean .
For the other part we have the mean and deviation provided the interval would be:
So then the interval would be (97.14, 99.5)
Given that,
Atmospheric Pressure = 14.7 psi
Cooking Pressure = 14.7 +11.1 = 25.8 psi
Take, Atmospheric Temperature = 25 °C
Cooking Temperature = ??
Since, we know that Gas equation is given by:
PV = nRT
or
P ∝ T
P1 / T1 = P2 / T2
14.7/ 25 = 25.8/ T2
T2 = 25*25.8/14.7
T2 = 43.87 °C
The cooking pressure will be 43.87 °C.
Answer:
$3.51
Explanation:
The energy (E) delivered by a system is the product of the power (P) dissipated by the system and the time (t) taken for the dissipation. i.e
E = P x t -----------------------(i)
Where;
The power (P) is the product of the current (I) flowing through the system and the voltage (V) across the system. i.e
P = I x V
Substituting P = I x V into equation (i) gives;
E = (I x V) x t
=> E = IVt --------------------(ii)
<em>From the question;</em>
Current (I) = 0.3A
Voltage (V) = 1.3V
time (t) = 75 hours = 75h
<em>Substituting these values into equation (ii) gives;</em>
=> E = 0.3 x 1.3 x 75
=> E = 29.25 Kwh
The energy delivered is 29.25Kwh
But in the U.S;
$0.12 = 1Kwh
=> 29.25Kwh = 29.25 x $0.12
=> $3.51
Therefore, the cost of the energy delivered by this battery per kilowatt hour is $3.51