Answer:
The acceleration of the car is
Explanation:
We are assuming rightward coordinate positive and all quantities are along this direction
We know,
where a - acceleration, v=velocity, t=time and x=displacement
multiply by dx in both sides
but we know
Therefore,
Here we integrate both sides with proper limits
x ranges from 0 to 110 as v ranges from 29 to 34
p = 0, r = 110, q = 29, s = 34
a is given as constant thus can be pulled out of the integration
Therefore,
Accelaration of the car is
Note:
Here moving to the right doesn't mean anything significant other than the fact that all quantities are pointing in that direction. Therefore obtained acceleration is also towards the right
If you know equation of motion for constant acceleration as
you can plug in values in this equation to obtain value of a
v - final velocity
u - initial velocity
s - displacement
Answer:
option C
Explanation:
The correct answer is option C.
The normal force is the force exerted by the biker on the inner vertical surface of the circular track.
When the biker move in the circular track centripetal force is acting on the biker which is being balanced by the normal force.
To overcome the gravitation force on the biker the velocity of the biker should be high such that centripetal acceleration of the biker can overcome the gravity force acting on the biker.
The kinetic energy of the person would be 1062.5J
<u>Explanation:</u>
Given:
Mass of the person, m = 85kg
Velocity, v = 5m/s
Kinetic energy, KE = ?
We know,
Substituting the value in the equation:
Therefore, the kinetic energy of the person would be 1062.5J
Answer:
b) a = -k / m x
, c) d²x / dt² = - A w² cos (wt+Ф)
, d) and e) T = 2π √m / k
h) a = - A w² cos (wt+Ф)
Explanation:
a) see free body diagram in the attachment
b) We write Newton's second law
Fe = m a
-k x = ma
a = -k / m x
c) the acceleration is
a = d²x / dt²
If x = A cos wt
v = dx / dt = -A w sin (wt
+Ф)
a = d²x / dt² = - A w² cos (wt+Ф)
d) we substitute in Newton's second law
d²x / dt² = -k / m x
We call
w² = k / m
e) substitute to find w
-A w² cos (wt+Ф) = -k / m A cos (wt+Ф)
w² = k / m
Angular velocity and frequency are related
w = 2π f
f = 1 / T
We substitute
T = 2π / w
T = 2π √m / k
g) v= - A w sin (wt+Ф)
h) acceleration is
a = - A w² cos (wt+Ф)