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3 years ago

Which formulas are used to calculate potential and kinetic energy

Physics

2 answers:

solniwko [45]3 years ago

8 0

Answer:

$\boxed{\bold { \large { \boxed {KE=\frac{1}{2} mv^2 \ , \ PE=mgh}}}}$

Explanation:

Kinetic energy formula

$\displaystyle KE=\frac{1}{2} mv^2$

Potential energy formula

$\displaystyle PE=mgh$

$\displaystyle KE \Rightarrow \sf kinetic \ energy \ (J)$

$\displaystyle PE \Rightarrow \sf potential \ energy \ (J)$

$\displaystyle m \Rightarrow \sf mass \ (kg)$

$\displaystyle v \Rightarrow \sf velocity \ (m/s)$

$\displaystyle g \Rightarrow \sf acceleration \ of \ gravity\ (m/s^2)$

$\displaystyle h \Rightarrow \sf height \ (m)$

aliya0001 [1]3 years ago

5 0

Answer:

PE=mgh

KE=<u>1</u> mv²

hope its helpful for u ..

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Scilla [17]

Answer:

1) C. The precise location of weather-related phenomena

2) C. It shows that the galaxies are moving farther away.

Explanation:

1) The global positioning system can be used in many ways, like in navigation, mapping and surveying the land. It is also used to observe the small changes taking place in the movement of objects on earth. They are usually used to study earthquakes.

2) When light from the galaxies is shifted towards the longer wavelengths, it is called red shift. When light shifts towards the shorter wavelengths, it is called blue shift. Big bang theory states how the primordial universe started expanding from a hot and dense singularity, in the process of evolution of the universe.

The universe is expanding always. Galaxies that are a part of the universe keep expanding and move farther away from each other. The galaxies that are very far off appear to move much faster than the nearby galaxies.

6 0

3 years ago

Consider a wire of a circular cross-section with a radius of R = 3.17 mm. The magnitude of the current density is modeled as J =

Sloan [31]

Answer:

The current is $I = 8.9 *10^{-5} \ A$

Explanation:

From the question we are told that

The radius is $r = 3.17 \ mm = 3.17 *10^{-3} \ m$

The current density is $J = c\cdot r^2 = 9.00*10^{6} \ A/m^4 \cdot r^2$

The distance we are considering is $r = 0.5 R = 0.001585$

Generally current density is mathematically represented as

$J = \frac{I}{A }$

Where A is the cross-sectional area represented as

$A = \pi r^2$

=> $J = \frac{I}{\pi r^2 }$

=> $I = J * (\pi r^2 )$

Now the change in current per unit length is mathematically evaluated as

$dI = 2 J * \pi r dr$

Now to obtain the current (in A) through the inner section of the wire from the center to r = 0.5R we integrate dI from the 0 (center) to point 0.5R as follows

$I = 2\pi \int\limits^{0.5 R}_{0} {( 9.0*10^6A/m^4) * r^2 * r} \, dr$

$I = 2\pi * 9.0*10^{6} \int\limits^{0.001585}_{0} {r^3} \, dr$

$I = 2\pi *(9.0*10^{6}) [\frac{r^4}{4} ] | \left 0.001585} \atop 0}} \right.$

$I = 2\pi *(9.0*10^{6}) [ \frac{0.001585^4}{4} ]$

substituting values

$I = 2 * 3.142 * 9.00 *10^6 * [ \frac{0.001585^4}{4} ]$

$I = 8.9 *10^{-5} \ A$

5 0

4 years ago

A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpole's shadow is 30 feet at

natka813 [3]

First you will want to sketch out both of the situations. It should be two sketches, one for the flagpole and one for the building.

To solve this, you will want to create a proportion.

Flagpole height/flagpole shadow=building height/building shadow

Therefore, it should look like this:
50/30= 300/x

Solve for x:
50x=9,000
X= 180 feet

YOUR ANSWER IS C.

7 0

3 years ago

A tall building is swaying back and forth on a gusty day. The wind picks up and doubles the amplitude of the oscillation. By wha

xz_007 [3.2K]

Answer:

by a factor of 2

Explanation:

Maximum speed of a body in simple harmonic motion relate to the amplitude by the following formula:

v ( maximum speed in m/s ) = x ( amplitude in meters ) √K /m where K is in N/m and m is kg

v is directly proportional to the amplitude and increases as the amplitude increases by a factor of 2

4 0

3 years ago

Gravity is affected by

mrs_skeptik [129]

Gravity is affected by mass and distance

3 0

4 years ago